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Sever21 [200]
3 years ago
7

Highest common factor of 92 and 42

Mathematics
2 answers:
GarryVolchara [31]3 years ago
8 0
To get the Greates Common Factor (GCF) of 92 and 42 we need to factor each value first and then we choose all the copies of factors and multiply them: 

<span><span>92:   22  23</span><span>42:   2 37 </span><span>GCF:   2    </span></span>

The Greates Common Factor (GCF) is:   2

 

<span>You can always share this solution</span>
kolezko [41]3 years ago
6 0
The correct answer is going to be 2



glad to help anytime

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Find the hcf*lcm for the number 105 and 125
Naily [24]

Answer:

15, 840.

Step-by-step explanation:

-HCM(GCM)

105's factor are 1, 3, 5, 7, <em>15</em>, 21, 35, 105.

125's factor are 1, 2, 3, 4, 5, 6, 8, 10, 12, <em>15</em>, 20, 24, 30, 40, 60, 120.

so, the answer is 15!

6 0
4 years ago
Trevor Linden, a former player for the Vancouver Canucks, is 1.93 m tall. On a hockey card, he is 5.4 cm tall. What scale was us
Anastaziya [24]

Answer:

scale  used to print the hockey card is 27/965

scale  used to print the hockey card in decimal  is 1/35.74

Step-by-step explanation:

we know that in scale problems

scale is used in drawing to enlarge or reduce size of object by a certain amount

scale = size of object in drawing/ actual size of object

Height of trevor = 1.93 m

we know that  1 m = 100 cm

Height of trevor in cm = 1.93 m*100 = 193 cm (actual size)

(this is done so that unit of measurement is same for card and trevor's height i.e cm)

Trevor's card on hockey card = 5.4 cm(size in drawing)

scale used = Trevor's card on hockey card /Height of trevor in cm

                    = 5.4/193 = 54/ 1930 = 27/965

scale  used to print the hockey card is 27/965

scale  used to print the hockey card in decimal  is 1/35.74

7 0
4 years ago
If cos thetha =-0.96 and (sec thetha)(sin thetha)&gt;0 find the value of tan thetha
kykrilka [37]
Cos(theta)=-0.96 <0
=>
theta is either in the 2nd or third quadrant.

cos(theta)=-0.96
=>
sec(theta)=1/cos(theta)=-1/0.96   <0

Given sec(theta)(sin(theta)>0
=> cos(theta)sin(theta)>0
=> cos(theta) and sin(theta) have the same sign, 
=> sin(theta)<0 
=>
theta is in the third quadrant. => tan(theta)>0

Given cos(theta)=-0.96
=>
|sin(theta)|=sqrt(1-(-0.96)^2)=sqrt(0.0784)=0.28 
=> sin(theta)=-0.28

Finally, 
tan(theta)=sin(theta)/cos(theta)=-0.28/-0.96
=7/24 
=0.29167 (to the fifth decimal place)
7 0
3 years ago
In
zzz [600]

Answer:

option 4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The height and radius of a cylinder are 23cm and 5cm what the volume?
vlabodo [156]

Answer:

Around 1806.42

8 0
3 years ago
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