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Sever21 [200]
4 years ago
7

Highest common factor of 92 and 42

Mathematics
2 answers:
GarryVolchara [31]4 years ago
8 0
To get the Greates Common Factor (GCF) of 92 and 42 we need to factor each value first and then we choose all the copies of factors and multiply them: 

<span><span>92:   22  23</span><span>42:   2 37 </span><span>GCF:   2    </span></span>

The Greates Common Factor (GCF) is:   2

 

<span>You can always share this solution</span>
kolezko [41]4 years ago
6 0
The correct answer is going to be 2



glad to help anytime

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A football team loses 4 yards on each 3 consecutive plays. Find the total change in yard from where the team started
BigorU [14]

Answer:

The Team started at 1st and 10 but finished at 4th and 22, so they lost 12 yards in 3 plays.

Step-by-step explanation:

6 0
3 years ago
Find the upper 20%of the weight?
meriva

Answer:

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Upper 20% of weights:

The upper 20% of the weighs are weighs of at least X, which is found when Z has a p-value of 0.8. So X when Z = 0.84. Then

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - \mu}{\sigma}

X = 0.84\sigma + \mu

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

6 0
3 years ago
PLEASE HELP!!!!
Anestetic [448]

Answer:

Option A is correct answer.

Step-by-step explanationa(x-h)x^{2} +k

If the given function is given as

f(x) =a(x-h)x^{2} +k

then vertex is (h,k) and Its domain is set of all real numbers

and range is given to be y ≥k for a>0

So here in the question the equation is given as

3(x-1)x^{2} +2

on comparing the equation with given standard equation

we get a=3 which is greater than zero

h =1 and k=2

therefore vertex is (1,2) ,Domain is set of all real number

and range is y≥2

That is option A is correct!

3 0
3 years ago
Read 2 more answers
2 ( 4x - 3 ) - 8 = 4 + 2x Giving me a headache
Advocard [28]

1 Expand.

8x-6-8=4+2x8x−6−8=4+2x

2 Simplify  8x-6-88x−6−8  to  8x-148x−14.

8x-14=4+2x8x−14=4+2x

3 Add 1414 to both sides.

8x=4+2x+148x=4+2x+14

4 Simplify  4+2x+144+2x+14  to  2x+182x+18.

8x=2x+188x=2x+18

5 Subtract 2x2x from both sides.

8x-2x=188x−2x=18

6 Simplify  8x-2x8x−2x  to  6x6x.

6x=186x=18

7 Divide both sides by 66.

x=\frac{18}{6}x=

​6

​

​18

​​

8 Simplify  \frac{18}{6}

​6

​

​18

​​   to  33.

x=3x=3

Done Hope this helps let me know if u have any questions thank you

4 0
3 years ago
Read 2 more answers
What is the domain of the following?<br><br><br><br> (-0,5)<br> (-4,9)<br> [-5,4]<br> (-0,00)
statuscvo [17]
Domain = all possible x values
You can see it starts from -5 and it goes till 4. Therefore domain -5 < x < 4

Solution: [-5,4]
3 0
3 years ago
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