Ferns are pointy and mosses is not!
Mountains is going to be windy an d cold
plants=semi warm
animals sorry idk
Answer:
The correct answer is - Chondroblasts; Fibroblasts
Explanation:
Mesenchymal progenitor cells will form chondrocytes combinedly called Chondroblasts that is responsible for the secretion of the rubbery matrix of cartilage.
Fibroblast on other hand produces fibers and ground substance. These ground substances and fibers make the matrix of the fibrous connective tissue.
Answer:
1. The parents genotypes could have been BO and AO
2. wire-hair
Explanation:
There are four possible blood types which are type A, B, AB, O. blood group is the classification of blood based on the presence or the absence of inherited antigenic substances on the surface of the red blood cells. They have hereditary basis and also rely on a series of alternative genes sometimes used in solving dispute of parental heritage. With the four possible blood groups, there are six possible genotypes and these are:
Blood type possible genotypes
Type A AA, AO
Type B BB, BO
Type AB AB
Type O OO
Thus, for parents with blood type B and A to give birth to a child with blood type O, it means their genotype could have been both BO and AO for them to be able to produce a child with OO. a cross between these two could give rise to OO.
Question 2
Wire hair is dominant (S) to smooth (s), thus wire hair could be in the homozygous (SS) and heterozygous form (Ss) and the smooth hair can only be expressed in the homozygous recessive form (ss).
thus, in a cross between homozygous wire haired and smooth haired, we will have:
homozygous wire haired homozygous smooth haired
P gen SS x ss
F1 gen. Ss
phenotype: wire haired
