Let x = the number of alternative schools.
Therefore, 2x - 4 = 48.
2x -4 +4 = 48 + 4
2x = 52
x = 26
Therefore, there are 26 alternative schools(You could check this answer by substituting x=26 into the equation above.).
Answer:
A
Step-by-step explanation:
The student must have thought that every single arrowhead is a line of symmetry, so since there are 10 arrowheads, there must be 10 lines of symmetry. This is incorrect because if you look closely at the diagram, each line has 2 arrowheads, so the student is overcounting by a factor of 2. They should have just counted the number of lines, not arrowheads. Therefore, there must be 10/2 = 5 lines of symmetry, not 10. Hope this helps!
Hi there!
PART A:
The system of equations we would use would be:
x + y = 22 (amount of items)
3x + 1y = 30 (cost)
Variables:
x = the amount of strawberry wafers bought at the price of $3
y = the amount of chocolate wafers bought at the price of $1
PART B:
To solve, we'll use substitution because we can easily isolate a variable using the first equation.
Work:
x + y = 22 (first equation)
y = 22 - x (isolating a variable)
3x + 1y = 30 (second equation)
3x + (22 - x) = 30 (substituting into the second equation)
2x + 22 = 30 (simplifying)
2x = 8 (subtracting)
x = 4 strawberry wafers
4 + y = 22 (substituting x into the first equation to solve for y)
y = 18 chocolate wafers
ANSWER:
They bought 4 strawberry wafers and 18 chocolate wafers.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:
2x-3y=2
x=6y-5
2(6y-5)-3y=2
use the distributive property.
2*6y=12y
2*-5=-10
12y-10-3y=2
combine like terms
12y-3y=9y
9y-10=2
add 10 to both sides.
9y-10+10=9y
2+10=12
9y=12
divide both sides by 9
9y/9=y
y=about 1.33
plug in the value of y in the expression equal to the value of x.
x=6(1.33)-5
solve
6*1.33=7.98
x=7.98-5
7.98-5=2.98
Step-by-step explanation:
x=2.98
y=1.33
