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Georgia [21]
3 years ago
14

Here are the prices of some items and the amount of sales tax changed on each item in Texas. What is the sales tax rate in Texas

?

Mathematics
1 answer:
fomenos3 years ago
3 0
The answer should be 6.25 percent I hope I helped
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How the heck r u supposed to round this? I tried and it says its wrong!
Rus_ich [418]

The result of division is 21.392

Rounded to the nearest tenth its  21.4  answer

(because the hundredth digit  is 9 so you add 1 to the tenth digit.)

5 0
3 years ago
The hourly median power (in decibels) of received radio signals transmitted between two cities
trasher [3.6K]

Using the lognormal and the binomial distributions, it is found that:

  • The 90th percentile of this distribution is of 136 dB.
  • There is a 0.9147 = 91.47% probability that received power for one of these radio signals is  less than 150 decibels.
  • There is a 0.0065 = 0.65% probability that for  6 of these signals, the received power is less than 150 decibels.

In a <em>lognormal </em>distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{\ln{X} - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of \mu = 3.5.
  • The standard deviation is of \sigma = \sqrt{1.22}

Question 1:

The 90th percentile is X when Z has a p-value of 0.9, hence <u>X when Z = 1.28.</u>

Z = \frac{\ln{X} - \mu}{\sigma}

1.28 = \frac{\ln{X} - 3.5}{\sqrt{1.22}}

\ln{X} - 3.5 = 1.28\sqrt{1.22}

\ln{X} = 1.28\sqrt{1.22} + 3.5

e^{\ln{X}} = e^{1.28\sqrt{1.22} + 3.5}

X = 136

The 90th percentile of this distribution is of 136 dB.

Question 2:

The probability is the <u>p-value of Z when X = 150</u>, hence:

Z = \frac{\ln{X} - \mu}{\sigma}

Z = \frac{\ln{150} - 3.5}{\sqrt{1.22}}

Z = 1.37

Z = 1.37 has a p-value of 0.9147.

There is a 0.9147 = 91.47% probability that received power for one of these radio signals is  less than 150 decibels.

Question 3:

10 signals, hence, the binomial distribution is used.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, we have that p = 0.9147, n = 10, and we want to find P(X = 6), then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{10,6}.(0.9147)^{6}.(0.0853)^{4} = 0.0065

There is a 0.0065 = 0.65% probability that for  6 of these signals, the received power is less than 150 decibels.

You can learn more about the binomial distribution at brainly.com/question/24863377

5 0
2 years ago
The cafeteria at a summer camp gives each camper 2/3 cup of juice for breakfast. This morning, 50 campers had juice for breakfas
zimovet [89]
It would be 33.33 because you have no change 50 into a fraction and divide that by 2/3

5 0
3 years ago
Read 2 more answers
A chef cooked 7 kilograms if the guests only ate 3 quaters of the amount he cooked how much did they eat
Oduvanchick [21]

5.25 kilograms.

3 quarters = 3/4

7 divided by 4 is 1.75

1.75x3 is 5.25.

6 0
2 years ago
The numbers 1 to 12 must be placed in the circles of the star shown on the right. The sums of the numbers in each row, and the s
gulaghasi [49]

Answer:

The numbers 1 to 12 must be placed in the circles of the star shown on the right. The sums of the numbers in each row, and the sum of the numbers in the six outer circles of the star, must be equal to 26. Arrange the numbers accordingly.

4 0
1 year ago
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