Let n represent number of times battery is charged.
We have been given that after each charging, a battery is able to hold only 97% of the charge from the previous charging. The battery was used for 18 hours on its first charge before it had to be recharged. We are asked to find the total number of hours the battery can be used over its lifetime.
We can see that our life of battery represents a geometric series, where 1st term is 18 and common ratio is 97% or 0.97.
We will use sum of geometric sequence formula to solve our given problem.
, where
= Sum of series,
= 1st term
r = Common ratio.
Therefore, the battery can be used for 600 hours over its lifetime.
The answer would be 15 centimeters each side.
Answer: (I'm sure you can plot them)
x-intercept:
(
−
6
,
0
)
y-intercept:
(
0
,
−
3
)
40 mg/0.4mL would be the right dosage on enoxaparin.
Answer:
d = 2750/Cos 48
Step-by-step explanation:
We need the value of the angle from the vertical axis
90 - 42 = 48°
We are trying to find the distance d which is the Hypotenuse of the right angled triangle formed.
The relationship between the adjacent and hypotenuse is help by the cosine of the angle between them
such that
Cos 48 = Adj/Hyp
Cos 48 = 2750/d
d Cos 48 = 2750
d = 2750/Cos 48