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UkoKoshka [18]
2 years ago
8

Coracias garrulus is a blue bird with an orange-brown back. The offspring of this bird have an effective defense mechanism. The

young birds vomit and cover themselves in a foul-smelling orange liquid when they sense a threat by predators. Which two systems alert the young bird to the danger and help produce the vomit it uses as a defense
Biology
1 answer:
miskamm [114]2 years ago
3 0

Answer:

The correct answer is - Nervous and digestive systems.

Explanation:

Coracias garrulus is a bluebird that has a unique defense mechanism in which it senses the danger or threat they vomit and cover themselves with their foul-smelling orange-yellow vomit.

The orange vomit or liquid store in the digestive system of the bird and when the bird's sense threatens it activates its nervous system which then intern sends a signal to the digestive system and the urge of vomit on its young ones and cover in that.

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Drag the terms on the left to the appropriate blanks on the right to complete the sentence. Terms may be used more than once.
Dima020 [189]

Hello. This question is incomplete. The full question is:

"Drag the terms on the left to the appropriate blanks on the right to complete the sentence. Terms may be used more than once.

1- free water

2- Solute

During osmosis, water diffuses across a selectively permeable membrane from the region of higher _______ concentration and lower _____ concentration to the side with lower _______ concentration and higher _______ concentration .

Answer:

During osmosis, water diffuses across a selectively permeable membrane from the region of higher free water concentration and lower solute concentration to the side with lower free water concentration and higher solute concentration

Explanation:

Osmosis is a biological process that takes place in cells and allows a substance to pass through the plasma membrane. Through osmosis, the plasma membrane, water can pass into and out of the cell through a gradient of solute concentration, that is, water passes from the place with the lowest concentration of solute to the place with the highest concentration, allowing thus the balance between the inter and extra cellular medium.

3 0
3 years ago
Describe how to find the hardness of an unknown mineral.
dsp73
The scratch test.

The scratch test is used by scientists and people who study rocks and minerals to determine the strength of the rock. They have the scratchers numbered one through ten and scratch the rock or mineral until the scratcher makes a mark in the mineral then they know the strength of the rock.
5 0
3 years ago
Read 2 more answers
A plant that produces wrinkled, green seeds was mated to a plant that produces phenotypically round, yellow seeds. In the F1 gen
sergejj [24]

Answer:

Genotype of the parental plant that produced round, yellow seeds is RRgg

Explanation:

Let us say that allele for round shape (R) is dominant over allele for wrinkled shape(r)

and allele for green color (G) is dominant over allele for yellow color of seed.  

So a wrinkled green seed will have genotype either "rrGG" or "rrGg"

Like wise a round, yellow seeds will have genotype either "RRgg" or "Rrgg"

It is given that In the F1 generation, half of the plants produced round, yellow seeds and the other half produced round, green seeds.

So if a cross is carried between rrGg and RRgg, the following offspring will be produces

rG          rG         rg         rg

Rg RrGg RrGg Rrgg Rrgg

Rg RrGg RrGg Rrgg Rrgg

Rg RrGg RrGg Rrgg Rrgg

Rg RrGg RrGg Rrgg Rrgg

So genotype “RrGg” gives round and green seeds

And genotype “Rrgg” gives round and green seed

Thus, genotype of the parental plant that produced round, yellow seeds is RRgg

5 0
3 years ago
Which of these statements are true?
kolbaska11 [484]
I think that the answer would be C
7 0
3 years ago
What percentage of offspring from a cross between a homozygous type A parent with a heterozygous Type A parent is expected to co
snow_lady [41]

The correct answer is option B, 50%

Let us take the following case:

Genotype of heterozygous parent - (Aa)

Genotype of homozygous parent – (aa)

Allele I  - (Aa)

Allele II – (aa)

The cross between the two is shown below:

Aa  X aa

Aa, Aa, aa, aa

There are 50 % Aa, and 50 % aa allele.  

Thus, the allele I (Aa) is 50 %.  

8 0
3 years ago
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