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SSSSS [86.1K]
3 years ago
12

Please help me

Mathematics
1 answer:
Ne4ueva [31]3 years ago
8 0

Answer:Answer:I can't read or see it

Step-by-step explanation:Answer:I can't read or see it

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I will give brainliest, Please help on this... Show ur work please and thank you
Elanso [62]

Answer:

n=9

Step-by-step explanation:

-5-4n=-41

+5        +5

---------------

-4n=-36

---------------

-4n/4=-36/-4

---------------

n=9

5 0
3 years ago
Find the lateral area of the right triangular prism below.<br> 5 in, 12 in, 13 in
labwork [276]

Step-by-step explanation:

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3 years ago
mrs paints yearly salary is $42,000 and increases $2,000 per year. mr paints yearly salary is $37,000 and increases $3,000 per y
den301095 [7]
It will take three years
8 0
3 years ago
What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4
Alecsey [184]

Answer:  f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: f(x)=\dfrac{3x^2}{x^2-4}

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}

i.e. y=\dfrac{3}{1}=3

Hence, f(x) will have horizontal asymptote at y=3.

3 0
4 years ago
The HCF of two numbers is 11, and their L.C.M is 368. If one number is 64, then the other
GaryK [48]
Erm 11 isn’t a factor of 64..?
6 0
3 years ago
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