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3 years ago

7

Which of the following formulas does not represent finding The height of a rectangular prism with a volume of 200 in.³, a length

of 4 inches, and a with of 5 inches?

1 answer:

joja [24]3 years ago

4 0

I believe it’s answer B ; 200= 20 • h

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r-ruslan [8.4K]

Just do this: 15/5 = 3 so she can have 3 of each color.

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3 years ago

A pair of dice is rolled, and the sum of the numbers is either 7 or 11. What is the probability of this event?

AfilCa [17]

Answer: $\dfrac{2}{9}$

Step-by-step explanation:

Let A be the event that the sum is 7 and and B be the event that the sum is 11 .

When two pair of dices rolled the total number of outcomes = $n(S)=6\times6=36$

The sample space of event A ={(1,6), (6,1), (5,2), (2,5), (4,3), (3,4)}

Thus n(A)= 6

The sample space of event B = {(5,6), (6,5)}

n(B)=2

Since , both the events are independent , then the required probability is given by :-

$P(A\cup B)=P(A)+P(B)\\\\=\dfrac{n(A)}{n(S)}+\dfrac{n(B)}{n(S)}=\dfrac{6}{36}+\dfrac{2}{36}=\dfrac{8}{36}=\dfrac{2}{9}$

Hence, the required probability = $\dfrac{2}{9}$

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3 years ago

Read 2 more answers

Two angles are complementary. The larger

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

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3 years ago

Find the first, fourth, and eighth terms of the sequence. A(n)=-2 × 2^N-1

11111nata11111 [884]

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4 years ago

A thermometer is taken from an inside room to the outside, where the air temperature is 20° f. after 1 minute the thermometer re

fomenos

The change in the temperature is proportional to the difference in temperatures. Let's call the initial temperature of the room and the thermometer $E_0$ and the current temperature $E(t)$ where $t$ is the elapsed time in minutes. The outside temperature is 20 F.

Newton's Law of Cooling:

$E(t) - 20 = (E_0 - 20) e^{- k t}$

We're given $E(1)=70 \textrm{ and } E(5)=45$

$70-20 = (E_0 - 20) e^{-k}$

$45-20 =(E_0 - 20) e^{-5k}$

Dividing,

$\dfrac{50}{25}=e^{4k}$

$k = \dfrac 1 4 \ln 2$

Now,

$E(t) - 20 = (E_0 - 20) e^{- k t}$

$E_0 = 20 + (E(t) - 20)e^{k t}$

$E_0 = 20 + (E(1) - 20)e^{k}$

$E_0 = 20 + (70 - 20)e^{\ln 2/4}$

$E_0 = 20 + 50 \cdot 2^{1/4} \approx 79.46 \textrm{ degrees F}$

3 0

4 years ago