Answer:
36x^6/y^10
Step-by-step explanation:
First evaluate the parentheses, 6x^3 x 6x^3 = 36x^6
y^5 x y^5 = y^10 ; remember m^k x m^r = m^k+r
final answer should be 36x^6/y^10
hope this helps :')
For the fulcrum to balance, the product of weight and distance on both sides of the fulcrum must be the same.
Let d1= x. since total distance is 12, we can write d2 = 12 - x
for the fulcrum to balance:
60x = 50(12 - x)
60x = 600 - 50x
110x = 600
x = 5.45
Thus, d1= 5.45
and
d2= 12 - d1 = 12 - 5.45 = 6.55
d1 = 5.45
d2 = 6.55
Answer:
Step-by-step explanation:
Bringing like terms on one side
4x - x = 7 + 1/2
3x = 7.5
x = 7.5/3
x = 2.5
Simplify the following:
((8 x^3 y^2 a^2 b^4)/4)^(-2)
8/4 = (4×2)/4 = 2:
(2 x^3 y^2 a^2 b^4)^(-2)
Multiply each exponent in 2 x^3 y^2 a^2 b^4 by -2:
(x^(-2×3) y^(-2×2) a^(-2×2) b^(-2×4))/(2^2)
-2×3 = -6:
(x^(-6) y^(-2×2) a^(-2×2) b^(-2×4))/2^2
-2×2 = -4:
(y^(-4) a^(-2×2) b^(-2×4))/(2^2 x^6)
-2×2 = -4:
(a^(-4) b^(-2×4))/(2^2 x^6 y^4)
-2×4 = -8:
b^(-8)/(2^2 x^6 y^4 a^4)
2^2 = 4:
Answer: 1/(4 x^6 y^4 a^4 b^8) thus the answer is A
Answer:
= 403
Step-by-step explanation:
the sum to n terms of an arithmetic series is
= 
(a + l) ← a is the first term and l the last term
here a = - 5 and l = 67 , then
= 
(- 5 + 67) = 6.5 × 62 = 403
