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3 years ago

11

Someone please help me I’ll give out brainliest please don’t answer if you don’t know

1 answer:

Luda [366]3 years ago

4 0

Answer:

Look below

Step-by-step explanation:

First, use order of operation or the three o's. That tells you to do what's in the parentheses first. Find out what the x next to the 2 is. Then subtract. If you look at the key, it shows you most of the answer. One black and one white both equal 1. Solve the question then sneak a calculator and simplify. Use the blocks to drag down as much as your final answer is.

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When x=5 and y=2 (x-y)^2

GrogVix [38]

Answer:

9

Step-by-step explanation:

new formula : (5 - 2) ^2

So 5- 2 equals 3. And 3 to the second power is 9

7 0

3 years ago

What's 9497÷16 as a whole number and remainder

brilliants [131]

Answer:

593 remainder 9

Step-by-step explanation:

Hi! If this helped please make this the brainliest answer, I'm on a goal to get 5 brainest answers, thanks!

5 0

4 years ago

Read 2 more answers

there is a ratio of 5 girls to 3 boys in the chorus.there are 24 boys in the chorus.how many girls are there

pshichka [43]

I think that the answer to this is 40 girls

24/3=8

8*5=40

hope this helps

3 0

3 years ago

What is the sum of 1/2 and 1/2

Annette [7]

The sum of 1/2 and 1/2 is 1

4 0

3 years ago

Read 2 more answers

Use the equation below to answer the question.

JulijaS [17]

Answer:

The signa notation to represent the first five ten f(x) is given by $f(x)=\sum\limits^{5}_{n=1}a_n$

Step-by-step explanation:

Given sequence is -5, -9, 13...

Let f(x) be the given sequence and is denoted by

$f(x)=\{-5,-9,-13,...\}$

Let the first term be $a_1, 2^{\textrm{nd}}$ term be $a_3,...$

ie, $a_1=-5,a_2=-9, a_3=-13,...$

To find the common difference d:

$d=a_2-a_1$

$=-9-(-5)$

$=-9-(+5)$

$d=-4$

$d=a_3-a_2$

$=-13-(-9)$

$=-13+9$

$d=-4$

Therefore the common difference d is -4 for given sequence f(x) with $a_1=-5$ and d=-4, the seqence f(x) is an arithmetic sequence

By defintion of arithmetic sequence

$a_n=a+(n-1)d\hfill(1)$

Now to find $a_4, a_5$ :

put n=4 in equation (1)

$a_4=a+(4-1)d$

$a_4=-5+(3)(-4)$ [since a=-5, d=-4]

$=-5-12$

$a_4=-17$

in equation (1)

$a_5=a+(5-1)d$

$a_5=-5+(4)(-4)$ [since a=-5, d=-4]

$=-5-16$

$a_5=-21$

Therefore $a_4=-17$ and $a_5=-21$

Therefore $f(x)=\{-5,-9,-13,-17,-21,...\}$

Now to represent the sum of the first five terms of f(x) using sigma notation as below

$f(x)=\sum_{n=1}^5 a_n$

where $\sum_{n=1}^5 a_n=a_1+a_2+a_3+a_4+a_5$

$-5-9-13-17-21$

$\sum_{n=1}^5 a_n=-65$

4 0

4 years ago