Answer:
5.83 = CD
Step-by-step explanation:
We can use the pythagorean theorem to solve
The legs are the x and y distances
x = (1- -4) = 5 units and y = 3 units
a^2+ b^2 = c^2
5^2 + 3^2 = c^2
25+9 = c^2
34 = c^2
Taking the square root of each side
sqrt(34) = c which is the distance from C to D
5.830951895 = CD
5.83 = CD
7x9=63
63÷2= 31.5x4
126= area of the triangles
7x7= 49= area of the square.
126+49= 175 ft
Answer:
Step-by-step explanation:
We're given one equation, we have to find the other equation and solve each for 200, and whichever has the lower x is the winner
for Jayden we are given

This looks to be a line. The y values are each separated by a common difference
We can use two points to describe the line

Now we can set both
and
equal to 200


Keiko's blog will reach 200 subscribers fastest.
Answer:


Step-by-step explanation:
Given

Required
Determine: 
First, we calculate f(x + h)



So, we have:





