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Nana76 [90]
3 years ago
7

Can someone help me please

Mathematics
1 answer:
mixer [17]3 years ago
5 0

9514 1404 393

Answer:

  ∠Z = 34°

  ∠T = 56°

Step-by-step explanation:

You can solve for x using the measure of the right angle:

  90 = 3x +6

  30 = x +2 . . . . . divide by 3

  28 = x . . . . . . . . subtract 2

Then the measure of T is ...

  ∠T = 2x° = 2(28)° = 56°

  ∠Z is its complement: 90° -56° = 34°

The angle measures are ...

  m∠Z = 34°

  m∠T = 56°

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Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!!!
Mamont248 [21]

Answer:

y= -x^2+5

Step-by-step explanation:

It normally expontionally goes up, so across the x axis is down so it is negative, and is is all scales up, so the start is 5 up from the origin on the y axis, so it would be y=-x+5

Hope this helped!

7 0
3 years ago
Please explain
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24-3x=-27
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7 0
3 years ago
What is the multiplicative inverse of 10/3?
nirvana33 [79]
<span>In mathematics, a multiplicative inverse or reciprocal for a number x, denoted by 1/ x or x −1, is a number which when multiplied by x yields the multiplicative identity, 1. The multiplicative inverse of a fraction a / b is b / a. For the multiplicative inverse of a real number, divide 1 by the number.</span>
3 0
3 years ago
Read 2 more answers
jake is younger than sophie. sophie is 14 years old. write an inequality that compares jakes age in years, j, to sophies age
matrenka [14]
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7 0
3 years ago
Read 2 more answers
Solve for x: 3/3x + 1/x+4 = 10/7x
Mekhanik [1.2K]
Given,

3/3x + 1/(x + 4) = 10/7x

1/x + 1/(x+4) = 10/7x

Because the first term on LHS has 'x' in the denominator and the second term in the LHS has '(x + 4)' in the denominator. So to get a common denominator, multiply and divide the first term with '(x + 4)' and the second term with 'x' as shown below

{(1/x)(x + 4)/(x + 4)} + {(1/(x + 4))(x/x)} = 10/7x

{(1(x + 4))/(x(x + 4))} + {(1x)/(x(x + 4))} = 10/7x

Now the common denominator for both terms is (x(x + 4)); so combining the numerators, we get,

{1(x + 4) + 1x} / {x(x + 4)} = 10/7x

(x + 4 + 1x) / (x(x + 4)) = 10/7x

(2x + 4) / (x(x + 4)) = 10/7x

In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by '(x + 4)'

{(2x+4) / (x(x + 4))} (7 / 7) = (10 / 7x) {(x + 4) / (x + 4)}

(14x + 28) / (7x(x + 4)) = (10x + 40) / (7x(x + 4))

Now both LHS and RHS have the same denominator. These can be cancelled. 

∴14x + 28 = 10x + 40
14x - 10x = 40 - 28
4x = 12
x = 12/4

∴x = 3



8 0
3 years ago
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