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lubasha [3.4K]
4 years ago
7

Scale of a model airplane to the actual airplane is 1 inch equals 10 feet. How many times longer the actual plane is than the mo

del airplane
Mathematics
1 answer:
WINSTONCH [101]4 years ago
6 0

Answer:

120 times

Step-by-step explanation:

If we want to find a qunatity is how many times as other quantity, we have to divide the large one by the small one (remember, same units).

Let's make both into inches.

We have 1 inch [model]

also

10 feet * 12 = 120 inches

Thus, we can say:

120/1 = 120 times

So, Actual Plane is 120 times than model airplane

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James decides to walk from school to the park tp play ball. The park is only 0.5 mile from the school. He leaves school at 3:15
aleksley [76]

Answer: 0.05\ \frac{mi}{min}

Step-by-step explanation:

For this exercise you need to remember the following formula:

V=\frac{d}{t}

Where "V" is the speed, "d" is the distance and "t" is time.

In this case, according to the information given in the exercise, you know that:

- James leaves his school at 3:15 and arrives at the park at 3:25. Then, you can identify that the time it takes him to go from his school to the park is:

t=10\ min

- The park is 0.5 miles from James' school. Therefore, you can identify that "d" is:

d=0.5\ mi

So, knowing those values, you can substitute them into the formula:

V=\frac{0.5\ mi}{10\ min}

Finally, evaluating, you get the following result:

V=0.05\ \frac{mi}{min}

6 0
3 years ago
What value of x makes the equation 4(5 - 7x) = 6 - 12x true?
Lemur [1.5K]

Answer:

4(5 - 7x) = 6 - 12

20-28x=6-12x

Subtract 20 from both sides

20-28x-20=6-12x-20

Simplify

-28x=-12x-14

Add 12x to both sides

-28+12x=-12x=-12x-14+12x

Simplify

-16x=-14

Divide both sides by -16

-16/-16 = -14/-16

Anw

7/8= 0.875

7 0
3 years ago
PLS HELP I WILL GIVE BRAINLIEST!!!!!!!
snow_lady [41]

Answer:

yes he is because they both eat half of there pizza.

7 0
3 years ago
A sailboat leaves port and sails 12 kilometers west and then 9 kilometers north. The sailboat is now kilometers from port
Luden [163]

Answer:  The sailboat is at a distance of 15 km from the port.

Step-by-step explanation:  Given that a sail boat leaves port and sails 12 kilometers west and then 9 kilometers north.

We are to find the distance between the sailboat from the port in kilometers.

Since the directions west and north are at right-angles, we can visualize the movement of the sailboat in the form of a right-angled triangle as shown in the attached figure.

The sailboat moves leaves the port at P and reach O after sailing 12 km west. From point O, again it moves towards north 9 km and reach the point S.

PS = ?

Using the Pythagoras theorem, we have from right-angled triangle SOP,

PS^2=OS^2+OP^2=9^2+12^2=81+144=225\\\\\Rightarrow PS=15~\textup{km}.

Thus, the sailboat is at a distance of 15 km from the port.

5 0
4 years ago
2 divided by square root 13 plus square root 11
coldgirl [10]

Answer: 3.87132498658 in other words 3.871

Step-by-step explanation:

4 0
2 years ago
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