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2 answers:
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Answer:
There is not enough evidence to state that mean laying rate μ for her hens is higher than the mean rate for all Golden Comets.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 5.0 eggs/week
Sample mean, = 5.2 eggs/day
Sample size, n = 39
Alpha, α = 0.05
Population standard deviation, σ = 1.1 eggs/Day
a) First, we design the null and the alternate hypothesis
We use one-tailed z test to perform this hypothesis.
b) Formula:
Putting all the values, we have
c) Now,
Since,
We fail to reject the null hypothesis and accept the null hypothesis. Thus, mean laying rate μ for Sarah's hens is same as the mean rate for all Golden Comets. There is not enough evidence to state that mean laying rate μ for her hens is higher than the mean rate for all Golden Comets.