Answer:
B. x(x) + (−6)(−3)
NOT equivalent to (x − 6)(x − 3)
Step-by-step explanation:
(x − 6)(x − 3)
= x^2 - 3x - 6x + 18
= x^2 - 9x + 18
A. (6 − x)(3 − x)
= 18 - 6x - 3x + x^2
= 18 - 9x + x^2
= x^2 - 9x + 18 ---->equivalent to (x − 6)(x − 3)
B. x(x) + (−6)(−3) = x^2 + 18 ----> NOT equivalent to (x − 6)(x − 3)
C. x2 − 3x − 6x + 18 = x^2 - 9x + 18 --> equivalent to (x − 6)(x − 3)
D. x(x − 6) − 3(x − 6)
= x^2 - 6x - 3x + 18
= x^2 - 9x + 18 ---->equivalent to (x − 6)(x − 3)
Answer:
The first table.
Step-by-step explanation:
1 cup = 1 * 16 = 16 tablespoons
2 = 2 * 16 = 32
3 = 3*16 = 48
4 = 4*16 = 64 and so on....
Answer:
△ABX ≅ △ACY, by reason that they are equal and congruent to each other.
I hope this answers your question.
Your interest would be $184.9 for 1 year so your total amount would be $3184.09
Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
