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Sergio039 [100]
3 years ago
11

7w = 87 ; w = 12 I need help

Mathematics
2 answers:
serious [3.7K]3 years ago
7 0
If W is equal to 12
and it is 7w=87
that means you are going to multiply 7(12)=87
but idk 7 time 12 is 84
Marysya12 [62]3 years ago
4 0
I don't know what the question is, and I'm guessing that you don't either. All I see here is two statements that disagree with each other. If 7w=87. then w is not 12. And if w=12 then. 7w is not 87.
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Gala2k [10]

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2 years ago
Which of these expressions is equal to 2(43 - p)?
nirvana33 [79]

Answer:

C. (2×43) - (2×p)

Step-by-step explanation:

The question is 2(43-p)

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Which will give us 86 - 2p

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5 0
3 years ago
Complete factorization f(x)=x^4-x^3-5x^2-x-6
Marianna [84]

The solution to the above  factorization problem is given as f′(x)=4x³−3x²−10x−1. See steps below.

<h3>What are the steps to the above answer?</h3>

Step 1 - Take the derivative of both sides

f′(x)=d/dx​​(x^4−x^3−5x^2−x−6)

Step 2 - Use differentiation rule d/dx​(f(x)±g(x))=d/dx​(f(x))±d/dx​(g(x))

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f′(x)=4x^3−3x2−d/dx​​(5x^2)−d/dx​​(x)−d/dx​​(6)

f′(x)=4x^3−3x^2−10x−d/dx​​(x)−d/dx​​(6)

f′(x)=4x^3−3x^2−10x−1−dxd​(6)

f′(x)=4x^3−3x^2−10x−1−0

Learn more about factorization:
brainly.com/question/25829061
#SPJ1

5 0
2 years ago
) Evaluating a polynomial limit analytically You should have learned by now the process for finding the derivative of a polynomi
wolverine [178]

Answer:

This code or is program to find a given value of derivative of  a polynomial.

Step-by-step explanation:

We know already how to apply or make the procedures mathematically talking so this short program will eventually help you how to find logic.

// libraries

#include <stdio.h>

#include <conio.h>

//use to control floating elements

float poly(float a[], int, float);

//main

int main()

{

// Enter the degree of polynomial equation

float x, a[10], y1;

int deg, i;

printf("Enter the degree of polynomial equation: ");

scanf("%d", &deg);

printf("Ehter the value of x for which the equation is to be evaluated: ");

// Enter the coefficient of x to the power

scanf("%f", &x);

for(i=0; i<=deg; i++)

{

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}

// The value of polynomial equation for the value of x

y1 = poly(a, deg, x);

 

printf("The value of polynomial equation for the value of x = %.2f is: %.2f",x,y1);

 

return 0;

}

/* function for finding the value of polynomial at some value of x */

float poly(float a[], int deg, float x)

{

float p;

int i;

 

p = a[deg];

 

for(i=deg;i>=1;i--)

{

 p = (a[i-1] + x*p);

}

 

return p;

}

8 0
3 years ago
What is the answer for this question
stich3 [128]
Inscribed ..........
5 0
3 years ago
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