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Vika [28.1K]
3 years ago
8

-20 + 6 = - +5 Approximate the solution to the equation above using three iterations of successive approximation. Use the graph

below as a starting point. 6 2 3 X х -6 14 - 2 6 2 -6 OA I -100 OB. 1 13 16 15 16 O C. 15 O D. r 021+​

Mathematics
2 answers:
vampirchik [111]3 years ago
5 0

Answer:

its b

Step-by-step explanation:

i did that test

Aleks [24]3 years ago
4 0

Answer:

Its a plus too

Step-by-step explanation:

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I have another question 8x−8≤−72. please help
AnnyKZ [126]
First move the -8 on the left to the right. this makes the inequality become 8x≤-64. Then you want to isolate the x by dividing 8x by 8, and make sure to do the same to -64. This makes it become x<span>≤-8, which is your final answer! Hope this helped :)</span>
8 0
4 years ago
Read 2 more answers
Please show your work
anyanavicka [17]

Answer:

Step-by-step explanation:

This is a parallelogram.  What we know about the diagonals is that they intersect each other at their midpoints.  In other words, QT = ST, and PT = RT.  So that gives us 2 equations:

If QT = ST, then

2x = y + 3

If PT = RT, then

x + 5 = y  Solving by substitution, plug x + 5 in for y in the first equation.

2x = x + 5 + 3 and

2x = x + 8 and

x = 7  Now plug in 7 for x to solve for y:

If x + 5 = y, then

7 + 5 = y and

y = 12

6 0
3 years ago
Need help please worth 50 points
Law Incorporation [45]
Here's how you simplify those. The rule for raising an exponent to an exponent is that you multiply them. The rule for dividing exponents with the same base is that you subtract the denomonator from the numerator.  So let's simplify the first one, which is actually the most confusing.
( \frac{ p^{5} }{ p^{-3} q^{-4}  } )^{ \frac{1}{4} }
Multiplying the exponents you get:
( \frac{ p^{ \frac{5}{4} } }{ p^{- \frac{3}{4} }  q^{-1} })
Subtracting the denominator from the numerator between the common base of p you get this:
\frac{ p^{ \frac{5}{4}- (-\frac{3}{4})  } }{ q^{-1} }
Doing that math gives you
\frac{ p^{2} }{ \frac{1}{q} } which equals \frac{ p^{2} }{1} * \frac{q}{1} which is p^{2}q, or the third one down.

The next one:
( \frac{ p^{2} q^{7}  }{ q^{4} } )^{ \frac{1}{2} }
simplifies to:
\frac{p* q^{ \frac{7}{2} } }{ q^{2} }
and subtracting the power of the denominator from the power of the numerator gives you:
p q^{ \frac{3}{2} }, which is the last choice.
( p^{6}q \frac{3}{2})^{ \frac{1}{3} }
simplifies to:
( p^{6* \frac{1}{3} } )( q^{ \frac{3}{2}* \frac{1}{3}  })
which simplifies very nicely to:
p^{2}q^{ \frac{1}{2} }, which is the first choice. The other one is found by process of elimination!
8 0
4 years ago
Please answer this question right now
likoan [24]

Answer:x= 0.5,−3

Step-by-step explanation:

4 0
3 years ago
What is the formula of volume ofba rhombic prism
Dimas [21]
Volume=the\ base\ area\ multiplied\ by\ the\ height\\\\if\ the\ base\ is\ a\ rhombus,\ \ then\ the\ base\ area= \frac{1}{2}\cdot e\cdot f \ \ \\\\and\ \ \ e,f\rightarrow\ the\ length\ of\ the diagonals\ of\ a\ rhombus\\\\V=\frac{1}{2}\cdot e\cdot f \cdot h\\\\and\ \ h\rightarrow\ the\ height\ of\ prism
8 0
4 years ago
Read 2 more answers
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