Interesting question. Let the 2 unknown sides be x and x+1.
Then (11 m)^2 + x^2 = sum of the squares of the 2 shortest sides
= (x+1)^2
121 + x^2 = x^2 + 2x + 1. Then 121 = 2x + 1, and 2x = 120, or x = 60.
Then the hyp. has length 60+1= 61.
We must check these results. Using the Pyth. Thm. (a^2 + b^2 = c^2),
11^2 + 60^2 = 61^2
121 + 3600 = 3721 This is true, so our answers are correct.
The longer side is 60 and the hyp. has length 61.
Answer:
The answer you are looking for is D
Step-by-step explanation:
Answer:
$193.67
Step-by-step explanation:
Let x = shirts
Let y = trousers
Let z = hat
4x + 4y + 2z = 660
9x + 9y + 6z = 1399
Divide the second equation by 3.
3x + 3y + 2z = 466.33
Subtract both equations
.
4x + 4y + 2z = 660
3x + 3y + 2z = 466.33
x + y = 193.67
So 1 shirt and 1 trouser will be $193.67
Answer:
629.3
Step-by-step explanation:
14.5x 6.2x7 =
volume.
have a nice day.
It's Probably 15, if I'm wrong correct me :P
