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nikitadnepr [17]
2 years ago
14

How do you solve the system of linear equations using this equation

Mathematics
1 answer:
solmaris [256]2 years ago
5 0
Are you trying to find the value of x and y?
You might be interested in
Find perimeter of rectangle when length = 4.6m and breadth = 360cm​
ivann1987 [24]

Answer:

16.4 m²

Step-by-step explanation:

length = 4.6 m

breadth = 360 cm = 360 ÷ 100 = 3.6 m

Perimeter = 2*(l + b)

                 = 2 * ( 4.6 + 3.6)

                 = 2 * 8.2

                  = 16.4 m²

7 0
2 years ago
Read 2 more answers
Barbara sells iced tea for $1.49 per bottle and water for $1.25 per bottle. She wrote an equation to find the number of bottles
yKpoI14uk [10]

Answer:

1.49x+1.25x=100

Step-by-step explanation:

5 0
2 years ago
Do you know works at a dinner she earn six dollars each hour plus tips in one week she worked 37 hours a week and earned 43 tips
lukranit [14]

Answer:

265

Step-by-step explanation:

The computation of the amount that should be make out together is shown below:

Let us assume the number of hours be x

And, the total money earned be y

Now the equation would be

y = 6x  + 43

= 6(37) + 43

= 265

5 0
2 years ago
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
2 years ago
What is the value for y in the following equation when x = -10?
nadezda [96]

Answer:

B.-38

Step-by-step explanation:

2x - 18 = y ...(1)

x = -10 (Given)

Now,

Put the value of x in equation (1) we get,

2(-10) - 18 = y

-20 - 18 = y

-38 = y

<em><u>y = -38</u></em>

Thus, the value of y is -38

6 0
3 years ago
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