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nikitadnepr [17]
3 years ago
14

How do you solve the system of linear equations using this equation

Mathematics
1 answer:
solmaris [256]3 years ago
5 0
Are you trying to find the value of x and y?
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3 years ago
Please answer ASAP! Compare and contrast the graphs of y < -x + 2 and y > -x + 2.
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The greater than and less than equal signs determine which way the graph is shaded. The graphs follow the same line but are shaded in different directions. y<-x+2 is shaded below the line because the sign is less than (<). y>-x+2 is shaded above the line because the sign is greater than (>).
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3 years ago
Select the best possible first step to solving the system by first eliminating the x variable. 4x 9y = 21 3x − 8y = 1 multiply t
STatiana [176]
Multiply the first equation by 3, and multiply the second equation by 4.
3 0
3 years ago
Read 2 more answers
PLEASE HELPP i know the answer is 12 but how?
zheka24 [161]
A^2+b^2=c^2

a^2+9^2=15^2

a^2+81=225
-81 -81

a^2= 144 (square root both sides)
a=12
4 0
2 years ago
Using the data in the table, use the exponential smoothing method with alpha=0.5 and a February forecast of 500 to forecast
Sever21 [200]

Answer:

Step-by-step explanation:

The formula to calculate the forecast could be determine by using the exponential smoothing method :

Ft = F(t-1) +  \alpha [A(t-1) - F(t-1)]

Where ,Ft is the Forecast for period t

F(t-1) is the Forecast for the period previous to t

A(t-1) is the Actual demand for the period previous to t

\alpha = Smoothing constant

To get the forecast for may and june   the above formula with \alpha =0.5 and april forecast of 500 will be used

For march

=500+0.5(520-500)\\\\=500+0.5\times20\\\\=500+10\\\\=510

For April

=510+0.5(535-510)\\\\=510+0.5\times25\\\\=510+12.5\\\\=522.5

For May

=522.5+0.5(550-5225)\\\\=522.5+0.5\times27.5\\\\=522.5+13.75\\\\=536.25

So forecast for May = 536.25

6 0
3 years ago
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