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The rate of disappearance of O2(g) under the same conditions is 2.5 × 10⁻⁵ m s⁻¹.
<h3>What is the rate law of a chemical equation? </h3>
The rate law of a chemical reaction equation is usually dependent on the concentration of the reactant species in the equation.
The chemical reaction given is;
The rate law for this reaction can be expressed as:
Recall that:
- The rate of disappearance of NO(g) = 5.0× 10⁻⁵ m s⁻¹.
- Since both NO and O2 are the reacting species;
Then:
- The rate of disappearance of NO(g) is equal to the rate of disappearance of O2(g)
Thus;
The rate of disappearance of O2 = 2.5 × 10⁻⁵ m s⁻¹.
Therefore, we can conclude that two molecules of NO are consumed per one molecule of O2.
Learn more about the rate law here:
Answer:
50 minutes
Explanation:
We can set this up as a rate * time = distance problem. We can set the rate at which Amanda travels to work to be x, since that quantity is unknown. The time it takes is given to be 60 minutes. This means that the total distance she travels to get to work is 60x. On the other hand, the way back home has more unknown quantities. The exact rate is unknown, but we do know that it is 20% more than the rate at which Amanda travels to work. This means that the rate is x + .20x, or 1.2x. We can set the time to be y, which means the total distance she travels to get back home is 1.2xy. We are told that Amanda uses the same route to get to and from work, which means 60x = 1.2xy. All we have to do now is solve this equation:
If we divide through by x and then isolate y, we get that it takes Amanda 50 minutes to get home