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Nadusha1986 [10]
3 years ago
12

Find the roots of x^4-6x^2+8

Mathematics
1 answer:
slavikrds [6]3 years ago
8 0

In my Knowledge

x^4-6x^2+8=0

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Answer:

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6 0
4 years ago
Please help me out and explain it to me​
a_sh-v [17]

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Step-by-step explanation:

You can solve this by first multiplying both sides of the fraction by the conjugate of the denominator.

In this case, the conjugate is (8 - 2i).

So:

\frac{3-5i}{8+2i} *\frac{8-2i}{8-2i}

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4 years ago
What is the reminder when (3x^3-2x^2+4x-3) is divided by (x^2+3x+3)
NARA [144]
(For full answer you might have to go to the comments)

Answer: 28x+30

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-(3x^3+9x^2+9x)
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-11x^2-5x-3

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So our remainder will be 28x+30
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4 years ago
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