See photo. Hope this helps
What is the electric field strength at a distance of 15 cm from a point charge that has 12
1 answer:
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Answer:
The value of x is .
Step-by-step explanation:
Please look at the figure attached to get more clear solution.
We have given:
FG||CB
And the line that cut the parallel line is transversal so, here BA is transversal
And alternate interior angles on transverse line are equal
So, ∠1=∠4
And ∠4=
Hence, ∠1=∠4=
And On FG the sum of angles will be
∠3+∠2+∠1=
+∠2+
=
Hence, ∠2=
Now, we know that the sum of interior angles is equal to the exterior angle:
Therefore, ∠2+∠5=∠6+∠7
On simplification we get:
Hence, the value of x is .
