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AURORKA [14]
3 years ago
15

What is the electric field strength at a distance of 15 cm from a point charge that has 12

Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0
The formula is E= kQ/ d^2

k is 9x10^9
i changed 15 cm to 0.15 m

=> 9x10^9 x 12 OVER (0.15)^2

the answer is 4.8x10^12 N/C

but this is the electric field.

to find electric field STRENGTH, it’s E= F/q and you did not give a value for the force
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Answer:

B) {56, 66, 95, 90, 57, 66, 69, 68, 76, 64, 51}

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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3(x - 2) + 48 = -3x
kow [346]

Answer: X=-7

Step-by-step explanation:

Using PEMDAS;

Step 1: Distribute the "3" in the part of the equation "3(x-2)"

3x - 6

Step 2: Consider the equation as a whole with the newly part of the equation from step 1, as it is a part of the equation

Therefore, re-written as,

3x - 6 + 48 = -3x

Step 3: Evaluate the re-written equation

Using basic mathematics skills, we can evaluate the following,

3x - 6 + 48 = -3x ➡ -6 + 48 = -6x ➡ 42 = -6x ➡ -7 = x

As shown, the answer is x=-7.

8 0
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ANTONII [103]
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6 0
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Answer:

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Step-by-step explanation:

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Point: (-2,2)

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