Since 6 + 8 = 14 this is the longest that the third side can be.
The answer is B
You have the following expressions given in the problem above:
(y^2/y-3)(y^2-y-6/y^2+y)
By applying the exponents properties, you can simplify it, as it shown below:
(y^2/y-3)(y^2-y-6/y^2+y)
(y^4-y^3-6y^2)/(y^3+y^2-3y2-3y)
(y^4-y^3-6y^2)/(y^3-2y2-3y)
Then, you have:
y^2(y^2-y-6)/y(y^2-2y-3)
(y^2-y-6)/(y^2-2y-3)
The answer is: (y^2-y-6)/(y^2-2y-3)
Answer:
ar ΔBDC=6 
ar ΔABD=8 
ar ΔABC=14 
Explanation:
Please take a look of attach figure.
We are given area of triangle ar ΔCDE=5 
ar ΔCDE=
------------(1)
ar ΔBDE=
------------(2)
Divide eq(2) by eq(1) and we get,


So, ar ΔBDE=1 
ar ΔBDC=ar ΔBDE+ ar ΔCDE
ar ΔBDC=1+5 = 6 
Similarly,


ar ΔABD=8 
ar ΔABC=ar ΔABD + ar ΔBDC
ar ΔABC=8+6 = 14 
Heres the answer hope it helps
Answer:
c reflection cross line a b