Answer:
P=41.72
Step-by-step explanation:
S=ACxDB/2
81.7=8.6xDB/2
81.7=4.3xDB|:4.3
19(mm)=DB
DO=19/2=9.5
OC=8.6/2=4.3
(O is the center of the rhombus, where two diagonals meet)
a²+b²=c² (DO²+OC²=DC²)
9.5²+4.3²=c²
90.25+18,49=c²
√108,74=√c²
c≈10.43
P=4c
P=4x10.43
P=41.72
Hope it helps:)
Hm
10 + 4 x 2 - 3
=10 + 8 - 3
=18 - 3
=15
The inequality is a > 12, which means a is greater than 12. This means that we are looking for numbers that are greater than 12 to place into the solution set. Options A and B are incorrect because 10 and 11 are both numbers less than 12, respectively. Option D is also incorrect because the inequality specifies that the numbers in the solution must be greater than 12, not equal to it, so 12 is not a solution.
This leaves option C as the correct answer, because all of the solutions in the set (13, 14, and 15) are greater than 12.
Therefore, your answer is C.
Hope this helps!
Answer:
(3,5)
Step-by-step explanation:
Answer: A single turquoise guppy costs $3.69
Step-by-step explanation:
Let us use "x" to represent the amount a single turquoise is sold and use "y" to represent that of the Glo fish.
Since Kellen bought 4 guppies and 3 glo fishes for $41.73:
4x + 3y = 41.73 --------eqn 1
Similarly, Danielle purchased 3 guppies and 5 Glo fish for $56.02:
Therefore 3x + 5y = $56.02 -----eqn2
The 2 equations are;
4x + 3y = 41.73 (eqn 1)
3x + 5y = 56.02 (eqn 2)
We then solve the simultaneous equations using substitution method:
From eqn 1,
4x + 3y = 41.73
4x = 41.73 - 3y
x = (41.73 - 3y)/4
Substitute x for (41.73 - 3y)/4 in eqn2.
3[(41.73 - 3y)/4 + 5y = 56.02
11y + 125.19 = 224.08
11y =98.89
y = 98.89/11
y = $8.99
So, 1 Glo fish costs $8.99
Then, substitute "y" for 8.99 in equation 1
4x + (3×8.99) = 41.73
4x + 26.97 = 41.73
4x = 41.73 - 26.97
4x = 14.76
x = 14.76/4
x = $3.69
Therefore 1 turquoise guppy costs $3.69
