This can be solved by factoring.
First, set the expression equal to zero.

Then, find two the factors of

whose sum is

.

Split

into these two factors.

Next, factor by grouping.

By the Zero Product Property, set each factor equal to zero.


These are the solutions. The Complex Conjugate Root Theorem and the Fundamental Theorem of Algebra both state that, in essence, real and imaginary solutions come in pairs of two and every polynomial of degree

has exactly

complex roots, but real roots are also complex roots. That sounds confusing, but this just means that you're done.
Your answers are -2 and 1/3. There are two real roots.
That seems so hard, sending prayers and brain cells to you.
Hey there!
2x + 2 = -4(x - 5)
2x + 2 = -4(x) - 4(-5)
2x + 2 = -4x + 20
ADD 4x to BOTH SIDES
2x + 2 + 4x = -4x + 20 + 4x
SIMPLIFY IT!
6x + 2 = 20
SUBTRACT 18 to BOTH SIDES
6x + 2 - 2 = 20 - 2
CANCEL out: 2 - 2 because it give you 0
KEEP: 20 - 2 because it help solve for the x-value
NEW EQUATION: 6x = 20 - 2
SIMPLIFY IT!
6x = 18
DIVIDE 6 to BOTH SIDES
6x/6 = 18/6
CANCEL out: 6/6 because it give you 1
KEE: 18/6 because it help solve for the x-value
NEW EQUATION: x = 18/6
SIMPLIFY IT!
x = 3
Therefore, your answer is: x = 3
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)