Log 3(x²+6x)=log(2x+12). I assume that 3 is a factor of a log with base 10:
if so, then:
log(3x²+18x)=log(2x+12)
==> 3x²+18x=2x+12==> 3x²+16x-12 = 0
solve this quadratic equation & you will find: x'=2/3 & x"=-6
I think its 8×4√16
Explenation:
√128 = 11.3
√16×√8=6.3
8√2= 11.3
so i think you see the patern there and the answer should be 11.3 or 6.3
8√4×√2= 19
19÷2=9.5
9.5÷2=4.75
since 5 is too big to put in the equation and equal 128 then its 4.
To find the second one just do 4², which is 16
So yeah 8×4√16
Answer:
x = 5/2 + sqrt(17)/2 or x = 5/2 - sqrt(17)/2
Step-by-step explanation:
Solve for x:
x^2 - 5 x + 2 = 0
Subtract 2 from both sides:
x^2 - 5 x = -2
Add 25/4 to both sides:
x^2 - 5 x + 25/4 = 17/4
Write the left hand side as a square:
(x - 5/2)^2 = 17/4
Take the square root of both sides:
x - 5/2 = sqrt(17)/2 or x - 5/2 = -sqrt(17)/2
Add 5/2 to both sides:
x = 5/2 + sqrt(17)/2 or x - 5/2 = -sqrt(17)/2
Add 5/2 to both sides:
Answer: x = 5/2 + sqrt(17)/2 or x = 5/2 - sqrt(17)/2
Answer:
there you go bro. 168 degrees for each angle
Step-by-step explanation:
To calculate the central angle visualize a circle in the center of the polygon. A circle has 360 degrees. Divide 360 by the number of sides and that will tell you the central angle size. So 360 divided by 30 equals 18 degrees.
To find the base angle use this formula
180(n-2)/n where n is the number of sides of a regular polygon.
When you plug in 30 for n
