Standard quadratic equation .. y = a x^2 + b x + c
<span>parabola 'a' not equal to zero </span>
<span>a<0 parabola opens downward </span>
<span>a>0 parabola opens upward </span>
<span>when |a| >>0 the parabola is narrower </span>
<span>when |a| is close to zero , the parabola is flatter </span>
<span>when the constant is varied it only effects the vertical position of the parabola , the shape remains the same</span>
The reason is the gotter of the right angle is 12
You go it right it's the first one
Answer:
Step-by-step explanation:
Lets solve the first half.
Second one:
Now compare.....Not the same right??
So your answer is:
Hope this helps :)
Answer:
104degrees
Step-by-step explanation:
From the given diagram, line LJ bisects KN, hence arcKL = arcHJ
Given
arHJ = 4x
arc KJ = x+39
Equating both
4x = x+39
4x - x = 39
3x = 39
x = 39/3
x = 13
Since arcHK = arcHJ + arcKJ
arcHK = x+39+4x
arcHK = 5x+39
arcHK = 5(13) + 39
arcHK = 65+39
arcHK = 104degrees
Hence the measure of arcHK is 104degrees