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Lostsunrise [7]
3 years ago
14

What is the answer to this (in attached photo)

Mathematics
1 answer:
Katena32 [7]3 years ago
5 0

Answer:

12

Step-by-step explanation:

Here is a list of each of the numbers until their factors add up to the same multiple:

Brendan - 4, 8, 12

Miguel - 6, 12

Jeron - 3, 6, 9, 12

- - - - -

Brendan would complete a lap about 3 times around 12 minutes.

Miguel would complete a lap about 2 times around 12 minutes.

Jeron would complete a lap about 4 times around 12 minutes.

IM CONCLUSION -

The answer is 12 minutes

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manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe
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\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32

he then turns around and grabs that money and sticks it for another 9 years,

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64

add both amounts, and that's how much is for the whole 21 years.
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3 years ago
Answer the following and SHOW YOUR SOLUTION.
Ivahew [28]

Answer: i need more information

Step-by-step explanation:

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