Answer:
18.75 ft
Step-by-step explanation:
The given scenario can be drawn as shown in the following attachment.
Given that,
and 
Therefore, 
ft
AB is the height of the house.
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer:
x = 0.5
y = -1/4 or -0.25
Step-by-step explanation:
x + 6y = 2
3x + 2y = 10
Multiply a number by any of the equations to get numbers of the same variable
3x + 18y = 6
3x + 2y = 10
3x - 3x = 0
NB: subtract evenly if u subtract down from top make sure u subtract down from top throughout
16y = -4
16y/16 = -4/16
y = -1/4 or -0.25
to find the x value, any where you see y u put in the y value(-0.25)
So u'll pick just one of the equations above
x + 6(0.25) = 2
x + 1.5 = 2
x = 1.5 + 2
x = 0.5
Answer:
2x-y=4
Step-by-step explanation:
y=mx+b
b is the y-intercept which is -4
y=mx-4
find m(slope)
(2,0) and (0,-4)
(-4-0)/(0-2)
-4/-2=2 m=2
y=2x-4
add 4 to both sides
y+4=2x subtract y
4=2x-y
It says write in standard form which looks like this: 3x + 5y = 4
