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timurjin [86]
3 years ago
10

What is the surface area? I need help help

Mathematics
2 answers:
o-na [289]3 years ago
5 0

Answer:

2400

Step-by-step explanation:

SA = 2(lw + lh + wh) = 2(20^2 + 20^2 + 20^2) = 2(3 * 20^2) = 2(3 * 400) = 2 * 1200 = 2400

yarga [219]3 years ago
4 0

Surface Area=2400

Step-by-step explanation:

To find the surface area we need to use this formula: Surface Area=6a^2

Where a is the side lengths that are being provided by the cube, now we plug in 20 as a into the formula.

Surface Area=6(20)^2

Surface Area=6(400)

Surface Area=2,400

Hope I helped, have a nice day :)

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$335.8
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5 0
2 years ago
Evaluate the function at the indicated values. f(x)= 6x^2+ 5x -12
seropon [69]

Step-by-step explanation:

We need to find the value of the function at the indicated value.

f(x)= 6x^2+ 5x -12

Indicated values are : f(-7), f(0), f(6), f(7)

To find f(-7), put x = -7 in the given function

f(-7)= 6(-7)^2+ 5(-7) -12=247

To find f(0), put x = 0 in the given function

f(0)= 6(0)^2+ 5(0) -12=-12

To find f(6), put x = 6 in the given function

f(6)= 6(6)^2+ 5(6) -12=234

To find f(7), put x = 7 in the given function

f(7)= 6(7)^2+ 5(7) -12=317

Hence, this is the required solution.

8 0
4 years ago
How much work is done by a man who uses a force of 7 Newtons to push a box 3 meters across the room?
ElenaW [278]

The formula to calculate work done is -

Work done ( in joule, J) = Force (in Newton) X Distance (in meters)

So, we will use the formula to calculate work done,

Here, force is given as = 7 newtons

Distance is given as = 3 meters

So, work done will be -

Work done ( in joule, J) = 7 Newtons X 3 Meters

<u>Work done ( in joule, J) = 21 J (in joule)</u>


7 0
3 years ago
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If f (x) = x + 7 and g (x) = StartFraction 1 Over x minus 13 EndFraction, what is the domain of (f circle g) (x)?
Rashid [163]

Answer:

R-{13}

Step-by-step explanation:

We are given that

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We have to find the domain of fog(x).

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Domain of f(x)=R

Because it is linear function.

Domain of g(x)=R-{13}

Because the g(x) is not defined at x=13

fog(x) is not defined at x=13

Therefore, domain of fog(x)=R-{13}

6 0
3 years ago
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What is the domain of this function?
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The domain is the origin of the arrow
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3 years ago
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