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3 years ago

How many solutions does the equation 2(x+1) = 2x+1 have?

Mathematics

1 answer:

elixir [45]3 years ago

4 0

Answer:

<h2><em><u>No Solutions</u></em></h2>

Explanation:

2(x + 1) = 2x + 1

Simplify both sides of the equation

2(x + 1) = 2x + 1

(2)(x) + (2)(1) = 2x + 1 [Distribute]

2x + 2 = 2x + 1

Subtract 2x from both sides

2x + 2 − 2x = 2x + 1 − 2x

2 = 1

Subtract 2 from both sides

2 − 2 = 1 − 2

0 = −1

<h2><u><em>This Is False, Therefore There Are No Solutions</em></u></h2>

- PNW

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3 years ago

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3 years ago

the volume of the cone is 25.12cm cubed, and the area of the base is 12.56cm squared.what is the height

Lady bird [3.3K]

Height of the cone having volume as $25.12 \text { cm}^{3}$ and base area $12.56 \text { cm}^{2}$ is 6 cm.

Solution:

Given that volume of cone = $25.12 \text{ cm}^{3}$

Area of base = $12.56 \text { cm}^{2}$

Need to determine height of the cone.

Formula for volume of the cone is as follows

$\mathrm{V}_{c}=\frac{1}{3} \pi r^{2}{h} \rightarrow (1)$

Area of circular base of cone = $A_{b}=\pi r^{2}$

Replacing $\pi r^{2} \text { by } A_{b}$ in equation (1), we get

$\mathrm{V}_{\mathrm{c}}=\frac{1}{3} \mathrm{A}_{\mathrm{b}} \mathrm{h}$

$\Rightarrow \frac{3 \mathrm{V} c}{\mathrm{A}_{\mathrm{b}}}=h$

$\Rightarrow h=\frac{3 \mathrm{v} c}{\mathrm{A}_{\mathrm{b}}} \rightarrow (2)$

In our case Volume of cone $V_c= 21.12 \text{ cm}^3$ and Area of base $A_b=12.56 \text { cm}^2$

On substituting the values of volume and area in equation 2 we get

$h=\frac{3 \times 25.12}{12.56}=6 \text{ cm }$

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3 years ago