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charle [14.2K]
3 years ago
15

kyle is making subs for a fundraiser. he has a roll of sub-wrap that is 14 3/8 feet long. on monday, he used 8 5/6 feet long of

sub-wrap. how much sub-wrap is left on the roll
Mathematics
1 answer:
Elanso [62]3 years ago
7 0
Answer: 5 11/24 ft
First you want to start by making the fractions by have the same denominator. You can just multiply 8 and 6 for this. You should have 14 18/48 and 8 40/48. Subtract them and you get 5 22/48. Simplify it and you get your answer.
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Rhonda has $4.85 in coins. If she has six more nickels than dimes and twice as many quarters as dimes, how many coins of each ty
Novay_Z [31]

Answer: nickels = 13, dimes = 7, quarters = 14

<u>Step-by-step explanation:</u>

First, set up the equations for each coin:

\begin {array}{c|c|c|l}\underline{\quad Type\quad }&\underline{Value}&\underline{Quantity}&\underline{\qquad \qquad \qquad Equation\qquad }\\ Nickel& \$0.05&6+d&0.05(6+d) = 0.30 + 0.05d\\Dime& \$0.10&d&\qquad 0.10(d)=0.10d\\Quarter& \$0.25&2d&\qquad 0.25(2d)=0.50d\\\end{array}

Next, the sum of the coins is $4.85 so substitute and solve for the variable:

   Nickels         +   Dimes  +   Quarters = Sum

(0.30 + 0.05d)  +    0.10d   +     0.50d   =  4.85

0.30 + 0.65d = 4.85

            0.65d = 4.55

                    d = 7

Lastly, plug the d-value into the quantity equation for the nickels and quarters to find their quantity.

nickels: 6 + d   = 6 + (7)   = 13

quarters: 2d   = 2(7)   = 14

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