1. Obey traffic laws. 2. You have the responsibility to drive safely. 3. Respect the rights of other drivers (or instead you can add 3. The financial responsibility of owning one)
I've been waiting all my life for this morning
Just to wake up next to you holding me
And your head is resting gently on my shoulder
Like you're whispering to me
I'm in love with you
I'm in love with you
So glad I found you
I'm in love with you
When we're leaving dreams and rolling back the covers
All at once we're getting ready for the day
It's when you look at me in the mirror while you're shaving
Before I go on my way, you say
I'm in love with you
I'm in love with you
You're the one I choose
'Cause I'm in love
Love is joy and love is pain
It's kissing in the rain
It's doing dishes when it's late
Isn't it, baby
It's the art of compromise
It's hellos and long goodbyes
It's the picture of our lives
Isn't it crazy
So I'll call you when I get to where I'm going
And I'll tell everyone we know you said hello
And without fail they'll ask me if I miss you
Of course I do, you know I do
'Cause I'm in love with you
I'm in love with you
You're the one I choose
I'm in love
I'm in love with you
I'm in love with you
I love you just the same as I did the day
I fell in love with you
The answer is B, design. This is the answer because you are arranging visual elements to design a work of art.
More like music people listen to like yoga or peaceful piano
<span>pH = pKa + log ([R-]/[RH])
Where pH is the pH of the buffer, [R-] is the concentration of the basic species, and [RH] is the concentration of the acidic species.
At pH 2.4, the amino group on glycine (pKa = 9.6) will be, for accounts and purposes, 100% protonated. This means our buffer will be dealing with the two ionic forms of the carboxyl group (pKa = 2.4).
When pH = pKa, the two species are in equilibrium. This can be seen using the HH equation:
2.4 = 2.4 + log ([R-]/[RH])
0 = log ([R-]/[RH])
1 = ([R-]/[RH])
[RH] = [R-]
Now we add in another equation, our conservation of mass.
M = [RH] + [R-]
where M is the molarity of the buffer
But since [RH] = [R-]:
M = 2 [RH]
0.2 = 2 [RH]
And we wind up with:
[RH] = [R-] = 0.1 M
Now to figure out the moles of each needed, we multiply by the volume of the buffer.
0.1 M * 0.1 L = 0.01 mol
This shows that to make 100 ml of 0.2 M glycine buffer, we'll need 0.01 mol of each species.
0.01 mol of 0.5 M HCl:
0.5 mol HCl / 1 L = 0.01 mol / v
solve for v
v/1 = 0.01 / 0.5 ==> v = 0.02 L or 20 mL
weight of glycine:
MW: 75.07 g/mol
0.01 mol glycine * (75.07g glycine / 1 mol) = 0.75 g glycine
And there's your answer
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To make this buffer you would add 0.75g glycine to 20 mL of 0.5 M HCl and fill with water until a 100mL volume was achieved.</span>
