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kodGreya [7K]
3 years ago
15

The pupil is the circular opening that allows light into the eye. An optometrist dilates a patient's pupil from 6 mm to 8 mm. Th

e scale factor under this dilation is ?
Mathematics
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

4/3

Step-by-step explanation:

Scale factor is a ratio of the length of side in one object to the length of a corresponding side of the other object.

In this case, the scale factor will be the ratio of the new dilated pupil size of the patient to the previous size of the pupil

This will be : 8/6 = 4/3

The scale factor is : 4/3

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Pls help asap for 13 pls and thank u
AysviL [449]
Answer:
The answer is 35.5 square units


Step-by-step explanation:

The shape represents a rectangle, a small triangle removed from it at the upper right corner and a bigger triangle is attached to it at the upper left corner.

We get this formula:
A(shape) = A(rectangle) - A(small triangle) + A(big triangle)
SO LET'S FIND EACH!

A(rectangle)= length x width
length= 8 units
width= 4 units
We get:
A(rectangle) =8x4= 32 square unit

A(small triangle)= (base x height)/2
base= 1 unit
height= 1 unit
We get:
A(small triangle) = (1x1)/2 = 1/2 = 0.5 square units

A(big triangle)= (base x height)/2
base= 2 units
height= 4units
We get:
A(big triangle)= (2x4)/2 = 8/2 = 4 square units

For the final result:
A(shape) = 32 - 0.5 + 4 = 35.5 square units


8 0
2 years ago
A rectangular plot of ground is 5 meters longer than it is wide. Its area is 20,000 square meters.
asambeis [7]
<span>w(w+5)=20,000 will help you find the answer</span>
7 0
3 years ago
Decide whether each table could represent a proportional relationship. In the essay box explain if the relationship could be pro
TEA [102]

Answer:

This table does represent a proportional relationship because the sale price and original price are going up at the constant rate of 10

Step-by-step explanation:

3 0
3 years ago
Find the product using model or drawing
antiseptic1488 [7]

Fraction multiplication involves multiplying the numerators and the denominators to get the numerator and the denominator of the product respectively

Please find the attached diagrams

1. \dfrac{2}{15}, 2. \dfrac{3}{8}, 3. \dfrac{1}{12}, 4. \dfrac{7}{21}, 5. \dfrac{3}{10}

6. 51, 7. 1, 8. 22, 9. \dfrac{36}{55}, 10. 5\dfrac{1}{3}

Reasons:

The process of multiplication of factors using a model includes;

  • Creating a table that have the number of rows and columns equal to the values in the denominator of the two fractions respectively
  • Shading the number of columns given by the numerator of the fraction that has a denominator equal to the number of columns in the table
  • Shading the number of rows given by the numerator of the  fraction that has a denominator equal to the number of rows in the table
  • Ensuring that the common area are shaded to a different color
  • Simplifying the result

1. \dfrac{2}{3}   \times \dfrac{1}{5} = \dfrac{2}{15}  

2. \dfrac{1}{2}   \times \dfrac{3}{4} = \dfrac{3}{8}

3. \dfrac{1}{4}   \times \dfrac{2}{6} = \dfrac{2}{24} = \dfrac{1}{12}

4. \dfrac{1}{7}   \times \dfrac{2}{3} = \dfrac{7}{21}

5. \dfrac{4}{8}   \times \dfrac{3}{5} = \dfrac{12}{40} = \dfrac{3}{10}

Second part

6. When calculating fractions, 'of' means to 'multiply by', therefore, we have;

\dfrac{17}{25}   \times 75= \dfrac{17}{25}   \times 25 \times 3 = 17 \times 3 =  51

7. \dfrac{7}{6}   \times \dfrac{24}{28} = \dfrac{7}{6}   \times \dfrac{6 \times 4}{7 \times 4} = \dfrac{7}{6}   \times \dfrac{6}{7 }  = 1

8. 12   \times 1\dfrac{5}{6} =6 \times 2   \times \dfrac{11}{6} =2   \times {11} = 22

9. \dfrac{4}{5}   \times \dfrac{9}{11} = \dfrac{4 \times 9}{5 \times 11} = \dfrac{36}{55}

10. 6\dfrac{2}{3}     \times \dfrac{12}{15} =\dfrac{20}{3}  \times \dfrac{12}{15} = \dfrac{4 \times 5}{3}  \times \dfrac{4 \times 3}{5 \times 3} = \dfrac{4}{3}  \times {4} = \dfrac{16}{3} = 5\dfrac{1}{3}

Learn more here:

brainly.com/question/2752457

7 0
3 years ago
If you know trig please help! Will give brainliest!
kaheart [24]

Answer:

sin^2α

Step-by-step explanation:

I will just  pose  x instead  of alpha  here to make things simpler

\tan ^2\left(x\right)\left(2\cos ^2\left(x\right)+\sin ^2\left(x\right)-1\right)\\\\

we know that sin^2x = 1 -  cos^2x so...

=\left(-1+1-\cos ^2\left(x\right)+2\cos ^2\left(x\right)\right)\tan ^2\left(x\right)

=\cos ^2\left(x\right)\tan ^2\left(x\right)

we can rewrite using trigonometric identities (tan = sin/cos)...

=\left(\frac{\sin \left(x\right)}{\cos \left(x\right)}\right)^2\cos ^2\left(x\right)\\= \sin ^2\left(x\right)

6 0
3 years ago
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