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Kitty [74]
3 years ago
12

A square has sides of length x. If the sides are all tripled in length, the area of the square is multiplied by

Mathematics
1 answer:
lyudmila [28]3 years ago
8 0

Answer:

3

Step-by-step explanation:

you would multiply by 3

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-6h plus 4 - 3plus h equals 11
olga55 [171]

- 6h + 4 - 3 + h = 11
So we start by combining like terms;
- 6h + h =  - 5h
4 - 3 = 1
Now we have;
- 5h + 1 = 11
We then subtract 1 from both sides;
- 5h + 1 = 11
- 5h = 10
Then we divide both sides by 5;
- 5h = 10
- 5h \div  - 5h =  h
10 \div  - 5h =  - 2
Leaving the final answer to be h = -2
5 0
3 years ago
There are (4^9)^5 x 4^0 books at the library. What is the total number of books at the library?
sergejj [24]

Answer:

You multiply 5 by the exponents and 4^0 is just 1, so 4^45•1=4^45. Hope this helped!

Step-by-step explanation:

3 0
3 years ago
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I need help with 15/20
Mrac [35]
.75 is the answer because it looks like division
8 0
3 years ago
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Can someone plzz help​
tankabanditka [31]

Answer:

it's 12 because

2×6=12

3×4=12

4×3=12

and all of them have twelve

6 0
3 years ago
The ratio of the side adjacent am acute angle and the hypotenuse. Adjacent/hypotenuse
diamong [38]

Answer:  The answer is cosine of that acute angle.


Step-by-step explanation:  We are to find the ratio of the adjacent side of an acute angle to the hypotenuse.

In the attached figure, we draw a right-angled triangle ABC, where ∠ABC is a right angle, and ∠ACB is an acute angle.

Now, side adjacent to ∠ACB is BC, which is the base with respect to this particular angle, and AC is the hypotenuse.

Now, the ratio is given by

\dfrac{\textup{adjacent side}}{\textup{hypotenuse}}=\dfrac{BC}{AC}=\dfrac{\textup{base}}{\textup{hypotenuse}}=\cos\textup{ of angle }ACB.

Thus, the ratio is cosine of the acute angle.

7 0
3 years ago
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