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Vera_Pavlovna [14]
3 years ago
12

A. 4.5 square 3 b.9 c. 9 square 2 b 9 square 3

Mathematics
1 answer:
LiRa [457]3 years ago
4 0
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Simplify 72y^4/8y^7<br><br> 72y^4<br> ———<br> 8y^7
mihalych1998 [28]

Step-by-step explanation:

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6 0
3 years ago
What is the equation of a line, in general form, that passes though points (-1,2) and (5,2)?
Tom [10]

Answer:

A

Step-by-step explanation:

To write the equation of the line. first calculate the slope using the slope formula.

m = \frac{y_2-y_1}{x_2-x_1} = \frac{2-2}{5--1}= \frac{0}{6} = 0

Since the slope of this line is 0, it is horizontal and has the form y=b where b is the y-coordinate. So y = 2 is the equation. In general form, it would be y-2 = 0

3 0
3 years ago
Which simplifications of the powers of i are correct? There may be more than one correct answer.
fredd [130]

\bf i^2=-1\qquad\qquad i^3=-i\qquad \qquad i^4=1 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ i^{22}\implies i^{(4\cdot 5)+2}\implies i^{4\cdot 5}i^2\implies (i^4)^5 i^2\implies 1^5(-1)\implies -1~\dotfill \bigotimes \\\\\\ i^{11}\implies i^{(2\cdot 5)+1}\implies (i^2)^5 i\implies (-1)^5(i)\implies -i~\dotfill \checkmark

\bf i^{21}\implies i^{(4\cdot 5)+1}\implies (i^4)^5 i\implies 1^5(i)\implies i~\dotfill \checkmark \\\\\\ i^{12}\implies i^{3\cdot 4}\implies i^3 i^4\implies (-i)(1)\implies -i\dotfill \bigotimes \\\\\\ i^{20}\implies i^{4\cdot 5}\implies (i^4)^5\implies 1~\dotfill \checkmark \\\\\\ i^{26}\implies i^{(4\cdot 6)+2}\implies (i^4)^6 i^2\implies 1^6(-1)\implies -1\dotfill \checkmark \\\\\\ i^{27}\implies i^{(4\cdot 6)+3}\implies (i^4)^6 i^3 \implies 1^6(-i)\implies -i\dotfill \bigotimes

6 0
3 years ago
Find f'(x) and state the domain of f':<br> f(x) = In (2x^2+1)
-Dominant- [34]

Answer:

f'(x) = \frac{4x}{2x^2+1}

Domain: All Real Numbers

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Derivative: \frac{d}{dx} [ln(u)] = \frac{u'}{u}

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = ln(2x² + 1)

<u>Step 2: Differentiate</u>

  1. Derivative ln(u) [Chain Rule/Basic Power]:                          f'(x) = \frac{1}{2x^2+1} \cdot 2 \cdot 2x^{2-1}
  2. Simplify:                                                                                       f'(x) = \frac{1}{2x^2+1} \cdot 4x
  3. Multiply:                                                                                                     f'(x) = \frac{4x}{2x^2+1}

<u>Step 3: Domain</u>

We know that we would have issues in the denominator when we have a rational expression. However, we can see that the denominator would never equal 0.

Therefore, our domain would be all real numbers.

We can also graph the differential function to analyze the domain.

5 0
3 years ago
Hi having a bit of trouble.
Lyrx [107]

Answer:

  P = 160/A

Step-by-step explanation:

For P to vary inversely with A, we must have P be proportional to the reciprocal of A. The constant of proportionality is given.

<h3>Inversely proportional</h3>

Two quantities are directly proportional if there is a constant of proportionality (k) that multiplies one of them to give the value of the other:

  y = kx

They are inversely proportional if the inverse of one of them can be multiplied by a constant of proportionality to give the value of the other:

  y = k(1/x) = k/x

In this problem, the variables P and A are said to be inversely proportional. That means the equation that relates them will be of the form ...

  P = k/A

You are given such a form with k=160, which is an appropriate value for the relation given by the problem. All you need to do is fill in the variable:

  P = 160/A

6 0
2 years ago
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