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alexandr402 [8]
2 years ago
14

Help please thank you!!!!!!!!!!!!!!!

Mathematics
1 answer:
Dvinal [7]2 years ago
8 0
I need 20 characters sooooooooo

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Write a recursive formula for
algol13

9514 1404 393

Answer:

  • a[1] = 3
  • a[n] = a[n-1] -7

Step-by-step explanation:

A recursive formula consists of two parts:

  • initialization (rule for the first term(s))
  • rule for the next term

When we look at the differences between terms in the sequence 3, -4, -11, ..., we find that they are constant at -7. That is each term can be found from the previous one by subtracting 7. This is our recursive rule. The first term is obviously 3, so the recursive formula is ...

  a[1] = 3

  a[n] = a[n-1] -7

5 0
3 years ago
What is the mean score Score<br> 90<br> 80<br> 70<br> 60
cupoosta [38]

Answer:

75

Step-by-step explanation:

Four scores....  add them together and divide by four

 (90 + 80 + 70 + 60) / 4 = 75

8 0
2 years ago
Simplify the expression below 6m^5+15m^2/3m^2
densk [106]

Answer:6m^5+5

Step-by-step explanation:

To simplify 6m^5+15m^2/3m^2

We get

6m^5+5

8 0
3 years ago
Domain<br> 6<br>range<br>8,7,-5,6<br> is this a function or not​
Fiesta28 [93]

Answer: That is a function!

Step-by-step explanation:

8 0
2 years ago
I'm not sure where to start and how to differentiate this.
Mazyrski [523]
The picture is not clear. let me assume y = (x^4)ln(x^3)

product rule :
d f(x)g(x) = f(x) dg(x) + g(x) df(x)

dy/dx = (x^4)d[ln(x^3)/dx] + d[(x^4)/dx] ln(x^3)
= (x^4)d[ln(x^3)/dx] + 4(x^3) ln(x^3)

look at d[ln(x^3)/dx]
d[ln(x^3)/dx]
= d[ln(x^3)/dx][d(x^3)/d(x^3)]
= d[ln(x^3)/d(x^3)][d(x^3)/dx]
= [1/(x^3)][3x^2] = 3/x
... chain rule (in detail)

end up with
dy/dx = (x^4)[3/x] + 4(x^3) ln(x^3)
= x^3[3 + 4ln(x^3)]

5 0
3 years ago
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