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Lena [83]
2 years ago
15

Find the perimeter of the object Help step by step please!

Mathematics
1 answer:
aliina [53]2 years ago
3 0

Answer:

29.42 units

Step-by-step explanation:

<u>1) Find the perimeter around the semi-circle</u>

To do this, we find the circumference of the circle using the given diameter:

C=\pi d where d is the diameter

Plug in 6 as the diameter

C=\pi (6)\\C=6\pi

Divide the circumference by 2

\frac{6\pi }{2} \\= 3\pi

Therefore, the perimeter around the semi-circle is 3π units.

<u>2) Find the perimeter around the rest of the shape</u>

Although it's impossible to determine the lengths of the varied sides on the right side of the shape, we know that all of those <em>vertical</em> sides facing the right add up to 6. We also know that all of those <em>horizontal </em>sides facing up add up to 7. Please refer to the attached images.

Therefore, we add the following:

7+6+7

= 20

Therefore, the perimeter around that area of the shape is 20 units.

<u>3) Add the perimeter around the semi-circle and the perimeter around the rest of the shape</u>

20+3\pi \\= 20+9.42\\= 29.42

Therefore, the perimeter of the shape is approximately 29.42 units.

I hope this helps!

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An interior automotive supplier places several electrical wires in a harness.Apull test measures the force required to pull spli
oksano4ka [1.4K]

Answer:

a) For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assumin Normal distribution

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical dsitribution

The result is on the figure attached.

b) For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

Step-by-step explanation:

For this case we have the following data:

28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4

The quantile-quantile or q-q plot is a graphical procedure in order to check the validity of a distributional assumption for a data set. We just need to calculate "the theoretically expected value for each data point based on the distribution in question".

If the values are asusted to the assumed distribution, we will see that "the points on the q-q plot will fall approximately on a straight line"

For this case our distribution assumed is normal.

Part a

For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assuming Normal distribution (0,1)

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical distribution

The result is on the figure attached.

Part b

For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

4 0
3 years ago
I don’t know what to do
n200080 [17]

Answer:

x = 7

y = 12

Step-by-step explanation:

To do this question you have to know your exponent rules, but also you need to know how to add fractions.

To multiply

6^(1/3) × 6^(1/4)

you can keep the 6 and just add the exponents.

That's why the answer is set up on the form 6^(x/y)

To add fractions, you need a common denominator, it is 12.

1/3 is 4/12.

1/4 is 3/12.

So 1/3 + 1/4

is the same as:

4/12 + 3/12

= 7/12

7/12 is the exponent you are looking for.

x = 7 and y = 12.

6^(1/3) × 6^(1/4)

=6^(7/12)

4 0
2 years ago
Please help me with this one to as soon as possible!
Naily [24]

Answer: A

Step-by-step explanation: Alright so- it says that Justin is both in half of his friends photos (which would be 15 photos) and half of his family's photos (6 photos). The total amount of photos period is 50 photos and 15 is greater than 6. Therefore I would say A.

8 0
3 years ago
Mr. Walker, a runner, asked students to find the unit rate of the winner of the first Boston Marathon in 1897. John J. McDermott
EleoNora [17]

Answer: 8.4 miles per hour

Step-by-step explanation:

Since, total distance = 24.5 miles,

Time taken =  175 \text{ minutes} = \frac{175}{60} \text{ hours} =\frac{35}{12} \text{ hours}

Thus,

\text{ The unit rate} = \frac{\text{ Total distance}}{\text{ Time taken}}

=\frac{24.5}{35/12}

=\frac{294}{35}

=8.4\text{ miles per hour}

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