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Lena [83]
3 years ago
15

Find the perimeter of the object Help step by step please!

Mathematics
1 answer:
aliina [53]3 years ago
3 0

Answer:

29.42 units

Step-by-step explanation:

<u>1) Find the perimeter around the semi-circle</u>

To do this, we find the circumference of the circle using the given diameter:

C=\pi d where d is the diameter

Plug in 6 as the diameter

C=\pi (6)\\C=6\pi

Divide the circumference by 2

\frac{6\pi }{2} \\= 3\pi

Therefore, the perimeter around the semi-circle is 3π units.

<u>2) Find the perimeter around the rest of the shape</u>

Although it's impossible to determine the lengths of the varied sides on the right side of the shape, we know that all of those <em>vertical</em> sides facing the right add up to 6. We also know that all of those <em>horizontal </em>sides facing up add up to 7. Please refer to the attached images.

Therefore, we add the following:

7+6+7

= 20

Therefore, the perimeter around that area of the shape is 20 units.

<u>3) Add the perimeter around the semi-circle and the perimeter around the rest of the shape</u>

20+3\pi \\= 20+9.42\\= 29.42

Therefore, the perimeter of the shape is approximately 29.42 units.

I hope this helps!

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Answer:

If this is the question you are referring to, then the answer is B, which is already highlighted for your convenience.

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8 0
3 years ago
If a town with a population of 1,000 doubles in size every 46 years, what will the population be 92 years from now?
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Step-by-step explanation:

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3 years ago
A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove
Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

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Substituting these values in formula, we get

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Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

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