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elena55 [62]
3 years ago
12

Help me out please :(?

Mathematics
2 answers:
Andre45 [30]3 years ago
7 0

Answer:

3x2+15x=18

Step 1: Subtract 18 from both sides.

3x2+15x−18=18−18

3x2+15x−18=0

Step 2: Factor left side of equation.

3(x−1)(x+6)=0

Step 3: Set factors equal to 0.

x−1=0 or x+6=0

x=1 or x=−6

Reika [66]3 years ago
5 0

Answer:

A

I worked them out myself so if their wrong uh please don't get mad I tried my best.

Step-by-step explanation:

3x (2) + 15x = 18                               3x (2) + 15x = 18

6x + 15x = 18                                     6x + 15x = 18  

-6x + -6x = 18                                            -18     -18

--------------------------                             ------------------------

0 + 9x = 18                                            6x + -3 = 0

   ------  -------                                         -3 +  -3

      18  18                                           --------------------

          x = 2                                              -3 + 0

                                                                    X = -3

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which ordered pair is a solution to the system of linear equations 1/2 x - 3/4 y = 11/60 and 2/5 x + 1/6 y = 3/10?
bekas [8.4K]

Value of x=\frac{2}{3}\,\,and\,\,value\,\,of\,\,y=\frac{1}{5}

Solution set is  (\frac{2}{3},\frac{1}{5})

Step-by-step explanation:

We need to solve the following system of equations:

\frac{1}{2}x-\frac{3}{4}y=\frac{11}{60}\,\,\,eq(1)\\\frac{2}{5}x+\frac{1}{6}y=\frac{3}{10}\,\,\,eq(2)

We can solve this using Substitution.

Isolate x in \frac{1}{2}x-\frac{3}{4}y=\frac{11}{60}

\frac{1}{2}x=\frac{11}{60}+\frac{3}{4}y\\ x=\frac{11}{30}+\frac{3}{2}y

Putting value of x in equation(2)

\frac{2}{5}(\frac{11}{30}+\frac{3}{2}y)+\frac{1}{6}y=\frac{3}{10}\\Solving:\\Taking\,\,LCM\,\,of\,\,5,6,10 \,\,we\,\,get: 30\\Multiply\,\,by\,\,LCM\\\frac{2}{5}(\frac{11}{30}+\frac{3}{2}y)\times30+\frac{1}{6}y\times30=\frac{3}{10}\times30\\Simplifying:\\12(\frac{11}{30}+\frac{3}{2}y)+5y=9\\\frac{22}{5}+18y+5y=9\\23y=9-\frac{22}{5}\\23y=\frac{45-22}{5}\\23y=\frac{23}{5}\\y=\frac{\frac{23}{5} }{23}\\y=\frac{1}{5}

Putting value of y=1/5 in x=\frac{11}{30}+\frac{3}{2}y

x=\frac{11}{30}+\frac{3}{2}\times\frac{1}{5} \\x=\frac{11}{30}+\frac{3}{10}\\x=\frac{11+3*3}{30}\\x=\frac{11+9}{30} \\x=\frac{20}{30}\\x=\frac{2}{3}

So, value of x=\frac{2}{3}\,\,and\,\,value\,\,of\,\,y=\frac{1}{5}

Solution set is  (\frac{2}{3},\frac{1}{5})

Keywords: System of linear Equations

Learn more about System of linear Equations at:

  • brainly.com/question/9045597
  • brainly.com/question/13168205
  • brainly.com/question/2115716

#learnwithBrainly

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Angelina_Jolie [31]

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Step-by-step explanation:

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The integral of sec θ can be proven by multiplying and dividing by sec θ + tan θ, then using ∫ du/u = ln|u| + C.

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∫ sec θ (sec θ + tan θ) / (sec θ + tan θ) dθ

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