1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elena55 [62]
3 years ago
12

Help me out please :(?

Mathematics
2 answers:
Andre45 [30]3 years ago
7 0

Answer:

3x2+15x=18

Step 1: Subtract 18 from both sides.

3x2+15x−18=18−18

3x2+15x−18=0

Step 2: Factor left side of equation.

3(x−1)(x+6)=0

Step 3: Set factors equal to 0.

x−1=0 or x+6=0

x=1 or x=−6

Reika [66]3 years ago
5 0

Answer:

A

I worked them out myself so if their wrong uh please don't get mad I tried my best.

Step-by-step explanation:

3x (2) + 15x = 18                               3x (2) + 15x = 18

6x + 15x = 18                                     6x + 15x = 18  

-6x + -6x = 18                                            -18     -18

--------------------------                             ------------------------

0 + 9x = 18                                            6x + -3 = 0

   ------  -------                                         -3 +  -3

      18  18                                           --------------------

          x = 2                                              -3 + 0

                                                                    X = -3

You might be interested in
1 milileter = 2 meters simplest ratio
masya89 [10]

Answer:

I think at least 2000 millimeters would make up around 2 meters

Step-by-step explanation:

1000 milimeters = 1 meter

1000 x 2 = 2000 millimeters

6 0
3 years ago
What steps would you use to plot (−3, −4, 0) in a 3-dimensional coordinate system?
eimsori [14]

Answer:

a. From the origin, move back 3 units and down 4 units

Step-by-step explanation:

Given:

The coordinates of a point in a 3-dimensional space is given as:

(-3, -4, 0)

The value of 'x' = -3

The value of 'y' = -4

The value of 'z' = 0

At the origin, the values of 'x', 'y', and 'z' are each equal to 0.

So, the coordinates of origin is (0, 0, 0). In order to reach the point (-3, -4, 0) from the point (0, 0, 0), we don't move along the z-axis as the 'z' value remains the same. We need to move along the 'x' and 'y' directions only.

Now, 'x' is equal to -3. Negative values of 'x' occur backwards from origin. So, we move back by 3 units. to reach the point (-3, 0).

Now, the value of 'y' is -4. Negative values of 'y' occur below the origin. So, we move down by 4 units to reach the point (-3, -4).

Therefore, the correct option is option (a)

A graph in 2 dimensional is shown in support of the answer.

8 0
3 years ago
Let [n] = 1 if n is odd and 0 if n is even, for all positive integer n. if [n] * [n+8] = 0, then what is one possible value of n
astra-53 [7]
[n][n+8]=0

if either or both of [n] and [n+8] are 0, i.e. if one or both of n and n+8 are even. But both will be even if n is even, and odd otherwise, so any even n will be a solution, e.g. n=2.
5 0
3 years ago
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
Let g(x)=-x^2+5x+4. Find g(p)
Alexandra [31]

g(p) = -p^2 + 5p + 4 (you just replace the dummy variable)

4 0
2 years ago
Other questions:
  • Use the formula r = (F/P)^1/n - 1 to find the annual inflation rate to the nearest tenth of a percent. A rare coin increases in
    11·1 answer
  • 4(x-6)&lt;-2x+6 what is the solution to the inequality <br> _
    5·1 answer
  • It is x miles from James City to Huntley and y miles from Huntley to Grover. How many miles is it from James City to Grover? To
    6·1 answer
  • A technician is testing light bulbs to determine the number of defective bulbs. The technician records the table below to show t
    9·2 answers
  • After reading the story “First Day of School,” pick up where the story left off and add a climax, falling action and resolution.
    9·1 answer
  • Which relationship in the triangle must be true ?
    15·2 answers
  • Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n 2 if heads comes up
    13·1 answer
  • How many solutions does 5-2x=4-2x+4+x
    14·2 answers
  • What is the missing divisor 18.3 ÷ ____ = 3.05
    6·2 answers
  • Please help! i’ve been stuck on this question for the longest.
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!