Answer:
![y=2(x+6)^2+7](https://tex.z-dn.net/?f=y%3D2%28x%2B6%29%5E2%2B7)
![(-6,7)](https://tex.z-dn.net/?f=%28-6%2C7%29)
Step-by-step explanation:
![y=2x^2+24x+79](https://tex.z-dn.net/?f=y%3D2x%5E2%2B24x%2B79)
Completing the square is a process of converting a quadratic equation in standard form into vertex form.
The first step in completing the square is grouping the quadratic and linear terms of the quadratic equation.
![y=(2x^2+24x)+79](https://tex.z-dn.net/?f=y%3D%282x%5E2%2B24x%29%2B79)
Factor out the coefficient of the quadratic term,
![y=2(x^2+12x)+79](https://tex.z-dn.net/?f=y%3D2%28x%5E2%2B12x%29%2B79)
Now complete the square, add a term to make the grouped part of the equation a complete square, then balance the equation.
![y=2(x^2+12x+36-36)+79](https://tex.z-dn.net/?f=y%3D2%28x%5E2%2B12x%2B36-36%29%2B79)
Simplify,
![y=2(x^2+12x+36)+79+(2)(-36)](https://tex.z-dn.net/?f=y%3D2%28x%5E2%2B12x%2B36%29%2B79%2B%282%29%28-36%29)
![y=2(x+6)^2+79-72](https://tex.z-dn.net/?f=y%3D2%28x%2B6%29%5E2%2B79-72)
![y=2(x+6)^2+7](https://tex.z-dn.net/?f=y%3D2%28x%2B6%29%5E2%2B7)
The x-coordinate of the vertex of the equation is equal to (-1) times the numerical part of the quadratic term, and the y-coordinate is equal to the constant.
![(-6,7)](https://tex.z-dn.net/?f=%28-6%2C7%29)
Answer:
3
Step-by-step explanation:
The slope formula is m=y2-y1/x2-x1
y2 is 71
y1 is 65
x2 is 7
x1 is 5
71-65 is 6
7-5 is 2
So the slope looks like this:
6/2
Simplify:
Which is 3
Hope this helps!
Answer:
(8x+12) feet.The perimeter when x=2ft is 28 feet.
Step-by-step explanation:
The solution is in the attached file.
Answer:
A.If the value of b is increased from 0, the graph moves up.
Step-by-step explanation:
Answer:
![A=(72+36\sqrt{3})\ mm^2](https://tex.z-dn.net/?f=A%3D%2872%2B36%5Csqrt%7B3%7D%29%5C%20mm%5E2)
Step-by-step explanation:
see the attached figure with letters to better understand the problem
Let
a ----> the height of rectangle in mm
b ---> the base of rectangle in mm
step 1
Find the base of rectangle
----> by segment addition postulate
substitute
![b=3+3+3+3=12\ mm](https://tex.z-dn.net/?f=b%3D3%2B3%2B3%2B3%3D12%5C%20mm)
step 2
Find the height of rectangle
---> by segment addition postulate
substitute the given values
![a=3+CG+3\\a=6+CG](https://tex.z-dn.net/?f=a%3D3%2BCG%2B3%5C%5Ca%3D6%2BCG)
Find the length sides CG
Applying the Pythagorean Theorem
![BG^2=BC^2+CG^2](https://tex.z-dn.net/?f=BG%5E2%3DBC%5E2%2BCG%5E2)
substitute the given values
![6^2=3^2+CG^2](https://tex.z-dn.net/?f=6%5E2%3D3%5E2%2BCG%5E2)
![CG^2=6^2-3^2](https://tex.z-dn.net/?f=CG%5E2%3D6%5E2-3%5E2)
![CG=\sqrt{27}\ mm](https://tex.z-dn.net/?f=CG%3D%5Csqrt%7B27%7D%5C%20mm)
simplify
![CG=3\sqrt{3}\ mm](https://tex.z-dn.net/?f=CG%3D3%5Csqrt%7B3%7D%5C%20mm)
therefore
![a=(6+3\sqrt{3})\ mm](https://tex.z-dn.net/?f=a%3D%286%2B3%5Csqrt%7B3%7D%29%5C%20mm)
step 3
Find the area of rectangle
![A=ab](https://tex.z-dn.net/?f=A%3Dab)
we have
![a=(6+3\sqrt{3})\ mm](https://tex.z-dn.net/?f=a%3D%286%2B3%5Csqrt%7B3%7D%29%5C%20mm)
![b=12\ mm](https://tex.z-dn.net/?f=b%3D12%5C%20mm)
substitute
![A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2](https://tex.z-dn.net/?f=A%3D%286%2B3%5Csqrt%7B3%7D%29%2812%29%3D%2872%2B36%5Csqrt%7B3%7D%29%5C%20mm%5E2)