When a 2 kg mass is hung on a vertical spring, it extends the spring by 2.00 m. what is the angular velocity ω (in rads/s) of th
e mass when it oscillates back and forth on this spring?
1 answer:
Using g = 9.81 m/s²:
By Hooke's law:
F = kx
k = F/x
k = (2 x 9.81) / 2
k = 2 N/m
ω = √(k/m)
ω = √(2/2)
ω = 1 rad/s
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