Answer: 0.6
Step-by-step explanation:
Answer:
3 seconds
Step-by-step explanation:
You want to set h(t)=3, then take the root such that t≠0. You would have:
3=3+48t−16t^2
Let's solve your equation step-by-step.
3=3+48t−16t2
Step 1: Simplify both sides of the equation.
3=−16t2+48t+3
Step 2: Subtract -16t^2+48t+3 from both sides.
3−(−16t2+48t+3)=−16t2+48t+3−(−16t2+48t+3)
16t2−48t=0
Step 3: Factor left side of equation.
16t(t−3)=0
Step 4: Set factors equal to 0.
16t=0 or t−3=0
t=0 or t=3
3 makes more sense than 0 because the ball can't have been in the air for 0 seconds.
So the ball was in the air for 3 seconds.
Answer:
Side a = 23 Side b = 28 Side c =46
Step-by-step explanation:
First set up your equation witch is x-5+x+x-5*2=69
Then Simplify x+-5+x+x+-10=69
Then combine like terms 3x-15=69
Add 15 to both sides
After you will get 3x=84
then divide both sides by 3
You will get x=28
Then go back to your question it says THE FIRST IS 5 CM SHORTER THAN THE SECOND SIDE. THE THIRD SIDE IS TWICE AS LONG AS THE FIRST SIDE. So that tells you that to find A, you do 28-5=23, to side b is x so its 28, and to find side c you do 28-5*2=46. So A=23, B=28, and C=46.
