What is the approximate volume of a cylinder with a height of 2 ft and a radius of 6 ft?
1 answer:
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You haven't provided the coordinates of C and D, therefore, I cannot provide an exact solution. However, I'll tell you how to solve this problem and you can apply on the coordinates you have.
The general form of the linear equation is:
y = mx + c
where:
m is the slope and c is the y-intercept
1- getting the slope:
We will start by getting the slope of CD using the formula:
slope = (y2-y1) / (x2-x1)
We know that the line we are looking for is perpendicular to CD. This meas that the product of their slopes is -1. Knowing this, and having calculated the slope of CD, we can simply get the slope of our line
2- getting the y-intercept:
To get the y-intercept, we will need a point that belongs to the line.
We know that our line passes through the midpoint of CD.
Therefore, we will first need to get the midpoint:
midpoint = (
)
Now, we will use this point along with the slope we have to substitute in the general equation and solve for c.
By this, we would have our equation in the form of:
y = mx + c
Hope this helps :)
The general form of the linear equation is:
y = mx + c
where:
m is the slope and c is the y-intercept
1- getting the slope:
We will start by getting the slope of CD using the formula:
slope = (y2-y1) / (x2-x1)
We know that the line we are looking for is perpendicular to CD. This meas that the product of their slopes is -1. Knowing this, and having calculated the slope of CD, we can simply get the slope of our line
2- getting the y-intercept:
To get the y-intercept, we will need a point that belongs to the line.
We know that our line passes through the midpoint of CD.
Therefore, we will first need to get the midpoint:
midpoint = (
Now, we will use this point along with the slope we have to substitute in the general equation and solve for c.
By this, we would have our equation in the form of:
y = mx + c
Hope this helps :)
Answer:
The domain of is restricted to
, and the domain of
is restricted to
.
Step-by-step explanation:
From Function Theory we know that domain of a function is the set of values such that an image exist. Let and
the function and its inverse, respectively.
At first glance we notice that function is a second order polynomial and every polinomial is a continuous function and therefore, there exists an image for every element of domain.
But domain of its inverse is restricted to every value of x so that , which means that
.
Finally, we concluded that following answer offers the best approximation to our result:
The domain of is restricted to
, and the domain of
is restricted to
.