Area of pool edge = Area of big rectangle - Area of the pool
Area of pool edge = Area of the pool = 40 × 60 = 2400 ft²
2400 = Area of big rectangle - 2400
Area of big rectangle = 2400 + 2400
Area of big rectangle = 4800
Length × width = 4800
From the diagram, we need the length to be [x + x] more than the length of the pool, where x is the distance from the pool edge to the patio edge.
We also need the width of the big rectangle to be [[x + x] more than the width of the pool.
Length = 60 + 2x
Width = 40 + 2x
Length × Width = [60+2x] × [40+2x]
4800 = 2400 + 120x + 80x + 4x²
0 = 4x² + 200x - 2400
0 = 4[x² + 50x - 600]
0 = x² + 50x - 600
0 = [x - 60] [x + 10]
x - 60 = 0 OR x + 10 = 0
x = 60 OR x = -10
We can only use the positive value of x since the context is length
Hence, x = 60
Answer:
I think the awnser is 27.9
Step-by-step explanation:
4.5*6.2=27.9
Answer:
16
Step-by-step explanation:
To start off this problem, we are given that the line AB is equal to the line CD. In addition to that, we are given that the line EF equally intersects line AB and line CD. This provides us proof that angle AGH is equivalent to angle DHG. From this information, we can solve this problem relatively easily.
Lets work with this equation:

Next, divide 80 by 5.


This means that x is equal to 16.