Which statements are correct for all values of x?

Drag each expression to show whether it is equivalent to −2.6−(−5.9) -2.6 x - -5.9 x , −2.6+(−5.9) -2.6 x + -5.9 x , or neither.

vredina [299]

Answer:

$-2.6x-(-5.9x)$ is equivalent to $-2.6x+5.9x$ and $5.9x+(-2.6x)$

$-2.6x+(-5.9x)$ is equivalent to $-2.6x-5.9x$ and $-5.9x+(-2.6x)$ .

The expressions which are equivalent to neither:

$-5.9x+2.6x$ and $5.9x-(-2.6x)$

Step-by-step explanation:

Given the expressions:

1) $-2.6x-(-5.9x)$

2) $-2.6x+(-5.9x)$

To find:

The expressions equivalent to the given expressions.

or the expressions which are not equivalent to any of the given expressions.

Solution:

First of all, let us solve the brackets from the given expressions.

$-2.6x-(-5.9x)$ can be written as $-2.6x+5.9x$ (because when we multiply a negative sign with negative, it becomes positive.)

Similarly $-2.6x+(-5.9x)$ can be written as $-2.6x-5.9x$ (because when we multiply a positive sign with negative, it becomes negative.)

Therefore, the answer is:

$-2.6x-(-5.9x)$ is equivalent to $-2.6x+5.9x$ and $5.9x+(-2.6x)$

$-2.6x+(-5.9x)$ is equivalent to $-2.6x-5.9x$ and $-5.9x+(-2.6x)$ .

The expressions which are equivalent to neither:

$-5.9x+2.6x$ and $5.9x-(-2.6x)$

7 0

3 years ago

I really need help with this ASAP 71 POINTS

e-lub [12.9K]

Working is a bit of a mess, but vertically she's correct, but she's incorrect horizontally

8 0

3 years ago

How do i solve this?

irakobra [83]

Answer:

mode: number that appears most

mode=4 and 7

mean: =3+4+5+6+7+8+9+10+11÷9=7

so mean is 7

8 0

2 years ago

Find the IQR (interquartile range). 19, 21, 18, 17, 18, 22,46

yanalaym [24]

Answer:

4.

Step-by-step explanation:

Step 1: Formula.

$IQR=Q3-Q1$

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Step 2: Explain/define.

The interquartile range is the difference between quartile 3 and quartile 1.
Quartile 1 is the median of the upper half of a data set.
Quartile 3 is the median of the lower half of a data set.
The median is the 'middle value.'

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Step 3: Order/arrange.

In order to find the median, you must first put the numbers in numerical order.

19, 21, 18, 17, 18, 22, 46

↓

17, 18, 18, 19, 21, 22, 46

The lower half of the data set, not including the median of the whole data set, is 17, 18, and 18.

The upper half of the data set is 21, 22, and 46.

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Step 4: Solve.

17, 18, 18

21, 22, 36

Next, we find the medians of both sets.

The median of the lower half is 18 (Q1).

The median of the upper half is 22 (Q3).

Lastly, we subtract Q3 from Q1.

$22-18=4.$

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Step 5: Conclude.

I, therefore, believe the interquartile range of this data set is 4.

3 0

2 years ago

Please use the pi button on your calculator.

Serjik [45]

Answer:

here

r=8cm

h=6cm

surface area of cylinder= 2πrh+2πr2

on substituting value we get

A=703.72cm²

Step-by-step explanation:

7 0

3 years ago