If sin(2x) = cos (x + 30%), what is the value of x?!
1 answer:
Answer:
x ∈ {20°, 120°, 140°, 260°}
Step-by-step explanation:
I find a graphing calculator useful for solving equations of this sort. Subtracting cos(x+30°) from both sides gives an expression that is zero when x has the appropriate value. The calculator is very good at finding zeros.
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We can make use of the formula for the sum of two sines.
sin(a) +sin(b) = 2sin((a+b)/2)cos((a-b)/2)
Then we can rewrite ...
sin(2x) -sin(x +120°) = 0
as ...
2sin((2x-(x+120°))/2)·cos((2x+(x+120°))/2) = 0
sin((x -120°)/2)·cos((3x +120°)/2) = 0 . . . . . divide by 2 and simplify a bit
This resolves to two equations according to the zero product rule.
x/2 -60° = k·180° . . . . . for some integer k
x = 120° +k·360° . . . . . for some integer k
And the other equation is ...
3x/2 +60° = (2k +1)·90° . . . . . for some integer k
3x/2 = k·180° +30° . . . . . . . . subtract 60°, eliminate parentheses
3x = k·360° +60°
x = k·120° +20° . . . . . for some integer k
The values shown in the Answer section above are the values of x in the range 0 to 360°: 20°, 120°, 140°, 260°.
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Answer:
About 0.6548 grams will be remaining.
Step-by-step explanation:
We can write an exponential function to model the situation. The standard exponential function is:
The original sample contained 510 grams. So, a = 510.
Each half-life, the amount decreases by half. So, r = 1/2.
For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.
Therefore, our function is:
One year has 365 days.
Therefore, the amount remaining after one year will be:
About 0.6548 grams will be remaining.
Alternatively, we can use the standard exponential growth/decay function modeled by:
The starting sample is 510. So, C = 510.
After one half-life (38 days), the remaining amount will be 255. Therefore:
Solving for k:
Thus, our function is:
Then after one year or 365 days, the amount remaining will be about: