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Kisachek [45]
3 years ago
12

Is 1/10, 1/4, and 1/8 more or less than 1/2​

Mathematics
1 answer:
ryzh [129]3 years ago
5 0

Answer:

They are less than 1/2

Step-by-step explanation:

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The equation 6.32=k2 shows that buying 2 bags of apples would cost 6.32. how much is it for one bag
seropon [69]

Answer:

3.16

Step-by-step explanation:

You would divide the 6.32 by 2 to get the amount for one bag

5 0
3 years ago
A force of 3 pounds acts in the direction of 42 degrees to the horizontal. The force moves an object along a straight line from
EastWind [94]

Answer:

11.37 lb-ft

Step-by-step explanation:

We are given that

Force,F=3 pounds

\theta=42^{\circ}

Let Point  A (3,7)  and point B(8,8)

We have to find the work done by the force.

d==

r=\mid d\mid=\sqrt{x^2+y^2}=\sqrt{5^2+1^2}=\sqrt{26} feet

We know that Work done by the force

W=Frcos\theta

Substitute the values

W=3\times \sqrt{26}cos42=11.37 lb-ft

Hence, the work done by the force =11.37 lb-ft

6 0
3 years ago
If an elephant could eat 2,500 pounds of food in 10 days how much can it eat in 1,000 days
Juliette [100K]

Answer:

The elephant could eat 250,000 pounds of food in 1000 days

Step-by-step explanation:


5 0
3 years ago
Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
3 years ago
If a board game was
Lunna [17]

Answer:

28%Right?

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5 0
3 years ago
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