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tatyana61 [14]
3 years ago
5

Exercise 2

Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0
1. C - multiply 4 and 6 first
2. C - multiply 5 and 3 first
3. B - subtract 8 and 2
4. B - subtract 19 by 3
5. B - multiply 32 and 4

Hope this helps
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Answer: The answer to this question is

A.n

Step-by-step explanation:

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Negetive 3 is less than 3x equal to 9
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The question is How long did it take each time 18 liters of water were drained?
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3 years ago
My brainy brother and sister added their ages together and got 15. When they multiplied their ages together, they got 54. How ol
Vinvika [58]

Given:

Sum of ages of brother and sister = 15

Product of their ages = 54

To find:

How old is the older one between the two of them?

Solution:

Let x be the age of brother and y be the age of sister.

Sum of ages of brother and sister = 15

x+y=15

x=15-y                ...(i)

Product of their ages = 54

xy=54

(15-y)y=54                [Using (i)]

15y-y^2=54

0=54-15y+y^2

Splitting the middle term, we get

54-15y+y^2=0

54-9y-6y+y^2=0

9(6-y)-y(6-y)=0

(6-y)(9-y)=0

Using zero product property, we get

(6-y)=0\text{ and }(9-y)=0

y=6\text{ and }y=9

If y=6, then using (i), we get

x=15-6

x=9

If y=9, then using (i), we get

x=15-9

x=6

Therefore, the age of older one is 9, the age of younger one is 6 and the difference between their ages is 3.

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