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Paul [167]
3 years ago
9

ABC and DEF are congruent triangles. Which of the following is known to be true?

Mathematics
1 answer:
Anna11 [10]3 years ago
4 0

If in triangles ABC and DEF, AB = DE, AC = DF, and angle A = angle D, then triangle ABC is congruent to triangle DEF. Using words: If 3 sides in one triangle are congruent to 3 sides of a second triangle, then the triangles are congruent.

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Answer:

12 x 3 = 36 + 33

Step-by-step explanation:

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What is square root of 5 show work
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Which statement is true about the given function? f(x) < 0 over the intervals (–infinity, –2.7) and (0.8, infinity). f(x) &lt
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4 years ago
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Determine whether the following lines represented by the vector equations below intersect, are parallel, are skew, or are identi
KiRa [710]

Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

the  lines represented by the vector equations are:

r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

NOTE:

Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

Thus;

r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

d_2 =(2, \ -4, \  +6)

s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

∴

\dfrac{d_1}{d_2}= \dfrac{-1}{2} = \dfrac{2}{-4}= \dfrac{-3}{-6}

Hence, we can conclude that r(t) and s(t) are parallel.

6 0
3 years ago
What is the gradient of the graph shown
Keith_Richards [23]

9514 1404 393

Answer:

  3

Step-by-step explanation:

The gradient is the ratio of "rise" to "run". Here, it appears the line crosses the y-axis at y = -1. It appears that it also crosses the grid intersection at (1, 2). This represents a "rise" (change in y) of (2 -(-1)) = 3, for a "run" (change in x) of (1 -0) = 1. Then the gradient is ...

  m = rise/run = 3/1 = 3

The gradient of the graph is 3.

5 0
3 years ago
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