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May someone help me with these to questions ASAP.. it’s an math question
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The graph shows the solution to be (x, y) = (-1, 3).
So,
The probability of drawing a yellow marble is
.
Since he replaces the marble after it is drawn out, the probability of drawing another yellow is the same:.
The probability of drawing a red marble is
.
In order to get the probability of drawing 2 yellow marbles and 1 red marble, given that each marble is replaced after it is drawn out, we must multiply the fractions together.
Because the order of the marbles doesn't matter, we will multiply the probability by 3.
The probability of drawing a yellow marble is
Since he replaces the marble after it is drawn out, the probability of drawing another yellow is the same:
The probability of drawing a red marble is
In order to get the probability of drawing 2 yellow marbles and 1 red marble, given that each marble is replaced after it is drawn out, we must multiply the fractions together.
Because the order of the marbles doesn't matter, we will multiply the probability by 3.
A graph shows the solutions to be
(x, y) = (-6, 312) or (6, 312)
To solve algebraically, remove a factor of 2 from the second equation and use that expression to substitute for y in the first equation.
10x^2 -(8x^2 +24) = 48
2x^2 = 72
x = ±√(72/2) = ±6
y = 8*36 +24 = 312
(x, y) = (-6, 312) or (6, 312)
To solve algebraically, remove a factor of 2 from the second equation and use that expression to substitute for y in the first equation.
10x^2 -(8x^2 +24) = 48
2x^2 = 72
x = ±√(72/2) = ±6
y = 8*36 +24 = 312