All categories

3 years ago

PLEASE HELP GIVING BRAINLIEST!!! If ABCD is a parallelogram, m Equation = X =

Mathematics

1 answer:

Iteru [2.4K]3 years ago

4 0

Answer:

x = 44°

Step-by-step explanation:

here's your solution

=> we know that the sum of (3x + 4°) + x° = 180°

=> 3x + x + 4° = 180°

=> 4x + 4° = 180°

=> 4x = 180° - 4°

=>. 4x = 176°

=> x = 176°/4

=> x = 44°

You might be interested in

Graph the function f(x)=(x-3)^2+2f(x)=(x−<img src="https://tex.z-dn.net/?f=3%29%5E%7B2%7D" id="TexFormula1" title="3)^{2}" a

charle [14.2K]

I believe that’s what your asking for
Sorry if it doesn’t help

8 0

4 years ago

I'm horrible with adding words to math, and I'm incapable of talking so I couldn't do the audio assignment.

aev [14]

Answer:

Do you have any key words from the unit?

Step-by-step explanation:

8 0

4 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

4 years ago

Use prime factorazations of 24 and 28 to find the lcm

makvit [3.9K]

it would be 2 bcs 24/2=12 and 28/2=14

3 0

3 years ago

Can somebody help me please?

madreJ [45]

Factor
(x+7)(x-2)

Proof
7-2=5
7*-2=-14

Zeros
x+7=0
x=-7

x-2=0
x=2

Final answer: C

3 0

3 years ago

Read 2 more answers