Answer:
6.0
Step-by-step explanation:
This involves using SOH CAH TOA.
we use Sin as we want to find x (which is side O, and we are given H).
So we get sin37 = O/H
= x/10
so x = 10 sin 37 = 6.018... = 6.0 to the nearest tenth.
Live Fund receive 
it they sold half thier holding in Marks Brothers.
<u>Solution:</u>
Given: Sale price of Live Fund holding = 5000 dollar
To find: Amount that Live Fund will get if they sell half of their holding in Marks Brothers.
Assume the total number of shares held by Live Fund in Marks Brothers as A
Therfore, half the holdings (or half the number of shares) of Live Fund will be 
.
Thus, if each share is valued at 
, then the total value of the number of shares sold will be as follows,
Hence, Live Fund will receive 
Answer:
13 ft/s
Step-by-step explanation:
t seconds after the boy passes under the balloon the distance between them is ...
d = √((15t)² +(45+5t)²) = √(250t² +450t +2025)
The rate of change of d with respect to t is ...
dd/dt = (500t +450)/(2√(250t² +450t +2025)) = (50t +45)/√(10t² +18t +81)
At t=3, this derivative evaluates to ...
dd/dt = (50·3 +45)/√(90+54+81) = 195/15 = 13
The distance between the boy and the balloon is increasing at the rate of 13 ft per second.
_____
The boy is moving horizontally at 15 ft/s, so his position relative to the spot under the balloon is 15t feet after t seconds.
The balloon starts at 45 feet above the boy and is moving upward at 5 ft/s, so its vertical distance from the spot under the balloon is 45+5t feet after t seconds.
The straight-line distance between the boy and the balloon is found as the hypotenuse of a right triangle with legs 15t and (45+5t). Using the Pythagorean theorem, that distance is ...
d = √((15t)² + (45+5t)²)
Answer:
3is the answer because t
s apply
Step-by-step explanation:
Answer:
A) 5x = y
B) 
Step-by-step explanation:
A is 5x = y because there are 5 pink hearts per the number of boxes (x) bought.
B uses the equation 2x is less than or equal to 100 because the teacher is spending 2 dollars per kid and can spend a maximum of 100.
The graph for this is attached.
