Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Answer:
P= - 16/11 or P= - 1 5/11 or P= - 1.45455
Step-by-step explanation:
Just trust my answer
Divide the largest one by the smallest one : for example, the number 4 is 42=2× larger than the number 2.
Indeed, If you multiply 2 by 42 you'll get 4.
Of course, if a number is n× larger than another, then this other is n× smaller than the first one.
It will of course work with floating point : 0.6×10.6≈0.6×1.6667=1 so 1 is ~1.6667 times larger than 0.6 while 0.6 is ~1.6667 smaller than 1.
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Answer:
The answer is "120".
Step-by-step explanation:
Given values:
differentiate the above value:
Answer:
173.4 cm^2
Step-by-step explanation:
Surface area of the cone=pi*r*l+pi*r^2=pi*(4)*(9.8+4)=173.4 cm^2
